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Find pairs of factors for the product 1440.

Mathematics

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Step-by-step solution

2 steps

To find possible multiplicand and multiplier pairs for a product of 1440, we need to find pairs of factors of 1440.

  1. Find the prime factorization of 1440.

    1440=144×10=(12×12)×(2×5)=(22×3×22×3)×(2×5)=25×32×511440 = 144 \times 10 = (12 \times 12) \times (2 \times 5) = (2^2 \times 3 \times 2^2 \times 3) \times (2 \times 5) = 2^5 \times 3^2 \times 5^1
  2. Combine these prime factors in different ways to form pairs of multiplicands and multipliers.

    Here are a few examples:

    • Example 1: Multiplicand: 10 Multiplier: 144

      10×144=144010 \times 144 = \boxed{1440}
    • Example 2: Multiplicand: 12 Multiplier: 120

      12×120=144012 \times 120 = \boxed{1440}
    • Example 3: Multiplicand: 20 Multiplier: 72

      20×72=144020 \times 72 = \boxed{1440}
    • Example 4: Multiplicand: 30 Multiplier: 48

      30×48=144030 \times 48 = \boxed{1440}
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