Hence find the LCm and gcd of 48 and 60

Mathematics

ScanSolve AI Answer

Answer

12
240

Step-by-step solution

2 steps

To find the LCM and GCD, we first need the prime factorization of 48 and 60. (These were determined in a previous step).
Prime factorization of 48=24×3148 = 2^4 \times 3^1
Prime factorization of 60=22×31×5160 = 2^2 \times 3^1 \times 5^1

  1. Find the Greatest Common Divisor (GCD).

    For the GCD, we take the lowest power of each common prime factor.
    The common prime factors are 2 and 3.
    The lowest power of 2 is 222^2.
    The lowest power of 3 is 313^1.

    GCD(48,60)=22×31=4×3=12GCD(48, 60) = 2^2 \times 3^1 = 4 \times 3 = 12
  2. Find the Least Common Multiple (LCM).

    For the LCM, we take the highest power of all prime factors present in either number.
    The highest power of 2 is 242^4.
    The highest power of 3 is 313^1.
    The highest power of 5 is 515^1.

    LCM(48,60)=24×31×51=16×3×5=240LCM(48, 60) = 2^4 \times 3^1 \times 5^1 = 16 \times 3 \times 5 = 240

    The GCD of 48 and 60 is 12\boxed{12} and the LCM is 240\boxed{240}.

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