I mean the samples solved below the table

Mathematics

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Answer

0.0024 mol0.0024 \text{ mol}

Step-by-step solution

2 steps

The 0.49 g0.49 \text{ g} mass was used as an example value in the sample calculation provided below the table to demonstrate how to calculate moles of KHP. It is not a mass directly taken from any of the specific trials (Trial 1, 2, or 3) listed in the table above.

Here's how the moles were calculated using that example mass:

  1. Identify the example mass of KHP.

    The sample calculation uses an example mass of KHP:

    Mass of KHP=0.49 g\text{Mass of KHP} = 0.49 \text{ g}

  2. Use the molar mass of KHP to calculate moles.

    The molar mass of potassium hydrogen phthalate (KHP) is 204.24 g/mol204.24 \text{ g/mol}.
    To find the moles, divide the mass by the molar mass:

    Moles of KHP=Mass of KHPMolar mass of KHP\text{Moles of KHP} = \frac{\text{Mass of KHP}}{\text{Molar mass of KHP}} Moles of KHP=0.49 g204.24 g/mol\text{Moles of KHP} = \frac{0.49 \text{ g}}{204.24 \text{ g/mol}} Moles of KHP=0.0024 mol\text{Moles of KHP} = \boxed{0.0024 \text{ mol}}
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