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I) What do you mean by the minimum point of a function? ii) The function y = 2x3 + ax2 + bx has critical points at x=2 and x=1. Find: (i) The values of a and b. (ii) The values of x for which y is min

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You've asked to solve the questions from the image. I've already completed question 4.a, 4.b, 4.c, and 4.d. I will now proceed with question 1.a.

a asks:

i) What do you mean by the minimum point of a function?

ii) The function y=2x3+ax2+bxy = 2x^3 + ax^2 + bx where aa and bb are constant, has critical points at x=2x=2 and x=1x=1. Find:
(i) The values of aa and bb.
(ii) The values of xx for which yy is minimum.
(iii) The minimum value of yy.

  1. Define the minimum point of a function.

    A minimum point of a function is a point where the function's value is less than or equal to the values at all nearby points within its domain. At a local minimum, the first derivative of the function is zero (if differentiable), and the second derivative is positive.

  2. Find the values of aa and bb.

    Given the function y=2x3+ax2+bxy = 2x^3 + ax^2 + bx.
    Critical points occur where the first derivative y′y' is equal to zero.

    First, find the first derivative y′y':

    y′=ddx(2x3+ax2+bx)y' = \frac{d}{dx}(2x^3 + ax^2 + bx) y′=6x2+2ax+by' = 6x^2 + 2ax + b

    The critical points are given as x=1x=1 and x=2x=2. This means y′=0y'=0 at these points.

    For x=1x=1:

    6(1)2+2a(1)+b=06(1)^2 + 2a(1) + b = 0 6+2a+b=06 + 2a + b = 0 2a+b=−6(Equation 1)2a + b = -6 \quad \text{(Equation 1)}

    For x=2x=2:

    6(2)2+2a(2)+b=06(2)^2 + 2a(2) + b = 0 6(4)+4a+b=06(4) + 4a + b = 0 24+4a+b=024 + 4a + b = 0 4a+b=−24(Equation 2)4a + b = -24 \quad \text{(Equation 2)}

    Now, solve the system of linear equations for aa and bb.
    Subtract Equation 1 from Equation 2:

    (4a+b)−(2a+b)=−24−(−6)(4a + b) - (2a + b) = -24 - (-6) 2a=−182a = -18 a=−182a = \frac{-18}{2} a=−9a = -9

    Substitute the value of a=−9a=-9 into Equation 1:

    2(−9)+b=−62(-9) + b = -6 −18+b=−6-18 + b = -6 b=−6+18b = -6 + 18 b=12b = 12

    The values of aa and bb are a=−9,b=12\boxed{a = -9, b = 12}.

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