Identify angles related to the diameter.

April 22, 2026Mathematics

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April 22, 2026

Answer

$\angle LTM = 90^\circ$ (angle in a semicircle)

Fresh day Mmapaseka, let's solve.

9.1 Prove that $MNPT$ is a cyclic quadrilateral

Step 1: Identify angles related to the diameter. Since $LOM$ is a diameter, the angle subtended by the diameter at any point on the circumference is $90^\circ$ . Therefore, $\angle LTM = 90^\circ$ (angle in a semicircle).

Step 2: Use the fact that $L, T, P$ are collinear. Since $LT$ is produced to $P$ , $L, T, P$ are collinear. Thus, $\angle PTM = \angle LTM = 90^\circ$ . This is an angle of the quadrilateral $MNPT$ .

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Fresh day Mmapaseka, let's solve. 9.1 Prove that MNPT is a cyclic quadrilateral Step 1: Identify angles related to the diameter.

Asked on April 22, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 22, 2026

Fresh day Mmapaseka, let's solve. 9.1 Prove that MNPT is a cyclic quadrilateral Step 1: Identify angles related to the diameter. Since LOM is a diameter, the angle subtended by the diameter at any point on the circumference is 90^. Therefore, LTM = 90^ (angle in a semicircle). Step 2: Use the fact that L, T, P are collinear. Since LT is produced to P, L, T, P are collinear. Thus, PTM = LTM = 90^. This is an angle of the quadrilateral MNPT. Step

Identify angles related to the diameter.

9.1 Prove that MNPTMNPTMNPT is a cyclic quadrilateral

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Identify angles related to the diameter.

9.1 Prove that MNPTMNPTMNPT is a cyclic quadrilateral

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9.1 Prove that $MNPT$ is a cyclic quadrilateral

9.1 Prove that $MNPT$ is a cyclic quadrilateral