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Identify b and c for x2 + 5x + 6.

Mathematics

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Answer

b

2 and 32 \text{ and } 3

(x + 2)(x + 3)

Step-by-step solution

3 steps

Step 1: Identify bb and cc for x2+5x+6x^2 + 5x + 6.
Comparing x2+5x+6x^2 + 5x + 6 with the general form x2+bx+cx^2 + bx + c:

Part a

The value of bb is 5\boxed{5}.

Part b

2 and 32 \text{ and } 3

The value of cc is 6\boxed{6}.

  1. Complete the table to find integers rr and ss such that their product is c=6c=6 and their sum is b=5b=5.

    Factors of 6Product of the two factorsSum of the two factorsResult
    1 and 61×6=61 \times 6 = 61+6=71 + 6 = 7product = 6 but sum ≠\neq 5
    2 and 32×3=62 \times 3 = 62+3=52 + 3 = 5product = 6 and sum = 5
    -2 and -3(−2)×(−3)=6(-2) \times (-3) = 6(−2)+(−3)=−5(-2) + (-3) = -5product = 6 but sum ≠\neq 5

    The two integers that correctly provide the values of bb and cc are 2 and 3\boxed{2 \text{ and } 3}.

  2. Rewrite x2+5x+6x^2 + 5x + 6 in the form x2+rx+sx+cx^2 + rx + sx + c.

    Using r=2r=2 and s=3s=3:

    x2+2x+3x+6x^2 + 2x + 3x + 6
  3. Factorize the expression using grouping and the distributive property.

    x2+2x+3x+6x^2 + 2x + 3x + 6

    Group the terms:

    (x2+2x)+(3x+6)(x^2 + 2x) + (3x + 6)

    Factor out common factors from each group:

    x(x+2)+3(x+2)x(x + 2) + 3(x + 2)

    Factor out the common binomial (x+2)(x + 2):

    (x+2)(x+3)\boxed{(x + 2)(x + 3)}
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