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Home > Mathematics Homework Help > Solution

Identify the average score (Moy.) and coefficient (Coeff.) for each subject.

Asked on March 28, 2026|Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on March 28, 2026
Step 1: Identify the average score (Moy.) and coefficient (Coeff.) for each subject. • ANGLAIS: Moy. $4.9$, Coeff. $4$ • FRANCAIS: Moy. $11$, Coeff. $4$ • EDUCATION A LA CITOYENNETE ET A LA MORALE: Moy. $13$, Coeff. $1$ • GEOGRAPHIE: Moy. $11$, Coeff. $1$ • HISTOIRE: Moy. $11.3$, Coeff. $2$ • INFORMATIQUE: Moy. $11$, Coeff. $2$ • MATHEMATIQUES: Moy. $7$, Coeff. $4$ • SCIENCES: Moy. $13$, Coeff. $2$ • EDUCATION ARTISTIQUE ET CULTURELLE: Moy. $12$, Coeff. $1$ • CONDUITE: Moy. $16$, Coeff. $1$ • ECONOMIE SOCIALE ET FAMILIALE (ESF): Moy. $2$, Coeff. $1$ Step 2: Calculate the total weighted score by multiplying each subject's average by its coefficient and summing the results. $$ \text{Total Weighted Score} = (4.9 \times 4) + (11 \times 4) + (13 \times 1) + (11 \times 1) + (11.3 \times 2) + (11 \times 2) + (7 \times 4) + (13 \times 2) + (12 \times 1) + (16 \times 1) + (2 \times 1) $$ $$ \text{Total Weighted Score} = 19.6 + 44 + 13 + 11 + 22.6 + 22 + 28 + 26 + 12 + 16 + 2 $$ $$ \text{Total Weighted Score} = 216.2 $$ Step 3: Calculate the total sum of coefficients. $$ \text{Total Coefficients} = 4 + 4 + 1 + 1 + 2 + 2 + 4 + 2 + 1 + 1 + 1 $$ $$ \text{Total Coefficients} = 23 $$ Step 4: Calculate the overall average by dividing the total weighted score by the total coefficients. $$ \text{Overall Average} = \frac{\text{Total Weighted Score}}{\text{Total Coefficients}} $$ $$ \text{Overall Average} = \frac{216.2}{23} $$ $$ \text{Overall Average} \approx 9.40 $$ The overall average is $\boxed{\text{9.40}}$.

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Home›Mathematics Homework Help›Identify the average score (Moy.) and coefficient (Coeff.) f…
Q

Identify the average score (Moy.) and coefficient (Coeff.) for each subject.

March 28, 2026|Mathematics
Identify the average score (Moy.) and coefficient (Coeff.) for each subject.

Identify the average score (Moy.) and coefficient (Coeff.) for each subject.

ScanSolve AI

ScanSolve AI Answer

Answered on March 28, 2026

Step 1: Identify the average score (Moy.) and coefficient (Coeff.) for each subject. • ANGLAIS: Moy. 4.94.94.9, Coeff. 444 • FRANCAIS: Moy. 111111, Coeff. 444 • EDUCATION A LA CITOYENNETE ET A LA MORALE: Moy. 131313, Coeff. 111 • GEOGRAPHIE: Moy. 111111, Coeff. 111 • HISTOIRE: Moy. 11.311.311.3, Coeff. 222 • INFORMATIQUE: Moy. 111111, Coeff. 222 • MATHEMATIQUES: Moy. 777, Coeff. 444 • SCIENCES: Moy. 131313, Coeff. 222 • EDUCATION ARTISTIQUE ET CULTURELLE: Moy. 121212, Coeff. 111 • CONDUITE: Moy. 161616, Coeff. 111 • ECONOMIE SOCIALE ET FAMILIALE (ESF): Moy. 222, Coeff. 111

Step 2: Calculate the total weighted score by multiplying each subject's average by its coefficient and summing the results. TotalWeightedScore=(4.9×4)+(11×4)+(13×1)+(11×1)+(11.3×2)+(11×2)+(7×4)+(13×2)+(12×1)+(16×1)+(2×1)Total Weighted Score = (4.9 \times 4) + (11 \times 4) + (13 \times 1) + (11 \times 1) + (11.3 \times 2) + (11 \times 2) + (7 \times 4) + (13 \times 2) + (12 \times 1) + (16 \times 1) + (2 \times 1)TotalWeightedScore=(4.9×4)+(11×4)+(13×1)+(11×1)+(11.3×2)+(11×2)+(7×4)+(13×2)+(12×1)+(16×1)+(2×1) TotalWeightedScore=19.6+44+13+11+22.6+22+28+26+12+16+2Total Weighted Score = 19.6 + 44 + 13 + 11 + 22.6 + 22 + 28 + 26 + 12 + 16 + 2TotalWeightedScore=19.6+44+13+11+22.6+22+28+26+12+16+2 TotalWeightedScore=216.2Total Weighted Score = 216.2TotalWeightedScore=216.2

Step 3: Calculate the total sum of coefficients. TotalCoefficients=4+4+1+1+2+2+4+2+1+1+1Total Coefficients = 4 + 4 + 1 + 1 + 2 + 2 + 4 + 2 + 1 + 1 + 1TotalCoefficients=4+4+1+1+2+2+4+2+1+1+1 TotalCoefficients=23Total Coefficients = 23TotalCoefficients=23

Step 4: Calculate the overall average by dividing the total weighted score by the total coefficients. OverallAverage=TotalWeightedScoreTotalCoefficientsOverall Average = \frac{Total Weighted Score}{Total Coefficients}OverallAverage=TotalCoefficientsTotalWeightedScore​ OverallAverage=216.223Overall Average = \frac{216.2}{23}OverallAverage=23216.2​ OverallAverage≈9.40Overall Average \approx 9.40OverallAverage≈9.40

The overall average is 9.40\boxed{9.40}9.40​.

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