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Determine the roots of f(x) = -x2 - 2x2 + 5x + 6.

Mathematics

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Graph of f(x) = −x² − 2x² + 5x + 6

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Key points of f(x) = −x² − 2x² + 5x + 6
Pointxy
x-intercept−0.810
y-intercept06
Maximum0.838.08
x-intercept2.470

Step-by-step solution

9 steps

2.1
Given the following set of ordered pairs for f(x)f(x): {(−2;3),(0;−1),(1;2),(2;0)}\{(-2; 3), (0; -1), (1; 2), (2; 0)\}.

2.1.1 Write the inverse, f−1(x)f^{-1}(x) as a set of ordered pairs.

  1. To find the inverse of a set of ordered pairs, swap the xx and yy coordinates for each pair.

    f−1(x)={(3;−2),(−1;0),(2;1),(0;2)}f^{-1}(x) = \{(3; -2), (-1; 0), (2; 1), (0; 2)\}

    The final answer is:

    f−1(x)={(3;−2),(−1;0),(2;1),(0;2)}\boxed{f^{-1}(x) = \{(3; -2), (-1; 0), (2; 1), (0; 2)\}}

    2.1.2 State whether f(x)f(x) is a function or a non-function.

  2. A relation is a function if each input (x-value) has exactly one output (y-value).

    The x-values in f(x)f(x) are −2,0,1,2-2, 0, 1, 2. Each x-value is unique and corresponds to only one y-value.
    The final answer is:

    Function\boxed{\text{Function}}

    2.2
    The figure below represents the graph of g(x):y=axg(x): y = a^x with domain x∈Rx \in \mathbb{R}. Point A lies on g(x)g(x) and the co-ordinates of A are (4;8)(4; 8).

    2.2.1 Determine the equation for g(x)g(x) and leave the answer in the form y=...y = ...

  3. Substitute the coordinates of point A(4;8)A(4; 8) into the equation y=axy = a^x.

    8=a48 = a^4
  4. Solve for aa.

    a=84a = \sqrt[4]{8} a=(23)14a = (2^3)^{\frac{1}{4}} a=234a = 2^{\frac{3}{4}}
  5. Write the equation for g(x)g(x).

    y=(234)xy = (2^{\frac{3}{4}})^x y=23x4y = 2^{\frac{3x}{4}}

    The final answer is:

    y=23x4\boxed{y = 2^{\frac{3x}{4}}}

    2.2.2 Determine the equation of g−1(x)g^{-1}(x). Give the answer in the form x=...x = ...

  6. Start with the equation for g(x)g(x)

    y=23x4y = 2^{\frac{3x}{4}}.

  7. To find the inverse, swap xx and yy.

    x=23y4x = 2^{\frac{3y}{4}}

    This equation is already in the requested form x=...x = ....
    The final answer is:

    x=23y4\boxed{x = 2^{\frac{3y}{4}}}

    2.2.3 Write down an equation for the asymptote of g−1(x)g^{-1}(x).

  8. The original function g(x)=23x4g(x) = 2^{\frac{3x}{4}} is an exponential function.

    Exponential functions of the form y=bxy = b^x have a horizontal asymptote at y=0y=0.

  9. The inverse function g−1(x)g^{-1}(x) is a logarithmic function.

    The asymptote of an inverse function is found by swapping the variables in the asymptote of the original function.
    If the asymptote for g(x)g(x) is y=0y=0, then the asymptote for g−1(x)g^{-1}(x) is x=0x=0.
    The final answer is:

    x=0\boxed{x = 0}
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