What does this electronic symbol represent?

It appears to be a series-parallel circuit with a voltage source at the bottom (12 V battery), two 4 Ω resistors in parallel on the upper branch, and a 6 Ω resistor in series with that combination.

Formula: $\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2}$

Substitute: $\frac{1}{R_p} = \frac{1}{4 \, \Omega} + \frac{1}{4 \, \Omega} = \frac{1}{2 \, \Omega^{-1}}$

Simplify: $R_p = 2 \, \Omega$

Formula: $R_\text{total} = R_p + R_s$

Substitute: $R_\text{total} = 2 \, \Omega + 6 \, \Omega = 8 \, \Omega$

Formula: $I_\text{total} = \frac{V}{R_\text{total}}$

Substitute: $I_\text{total} = \frac{12 \, \text{V}}{8 \, \Omega} = 1.5 \, \text{A}$

Formula: $V_s = I_\text{total} \times R_s$

Substitute: $V_s = 1.5 \, \text{A} \times 6 \, \Omega = 9 \, \text{V}$

Formula: $I = \frac{V_p}{R}$

Substitute for each: $I_1 = I_2 = \frac{3 \, \text{V}}{4 \, \Omega} = 0.75 \, \text{A}$

Total current = 1.5 A, V across 6 Ω = 9 V, I through each 4 Ω = 0.75 A

1.5 A