Name the circuit symbols.

Hey Arbenarh, good to see you again. Part (c) Step 1: Name the circuit symbols. II: Resistor* III: Switch* IV: Voltmeter* Step 2: Draw the circuit diagram. The circuit diagram should show a cell (I), a switch (III), a resistor (II), an ammeter (V) in series with the resistor, and a voltmeter (IV) in parallel across the resistor. (0,0) to[battery] (0,2) to[switch] (2,2) to[ammeter] (4,2) to[R, l_=II] (6,2) node[right] (6,2) -- (6,0) (6,0) -- (0,0) (6,2) to[voltmeter, v_=IV] (6,0) ; Step 3: Determine the value of II (Resistance). Given: Ammeter (V) reading = Current (I) = 5 A Voltmeter (IV) reading = Voltage (V) = 15 V Using Ohm's Law, V = IR. R = (V)/(I) Substitute the given values: R = 15\, V5\, A R = 3\, The value of II (resistance) is 3 . Part (d) Step 1: Identify solutions based on pH values. (i)(a) pH value equal to 7: Solution C (NaCl is a neutral salt). (i)(b) pH value equal to 14: None of the solutions would have exactly pH 14. However, Solution E (NaOH) is the strongest base listed, with a pH of 13 for 0.1 mol dm^-3. Assuming the question implies the strongest base, the answer would be Solution E*. Step 2: Classify solutions. (ii)(a) Strong acid: Solution A (HCl). (ii)(b) Neutral: Solution C (NaCl). (ii)(c) Weak base: Solution D (NH_3). Step 3: Suggest the pH value of solution A. Solution A is 0.1 mol dm^-3 HCl, which is a strong acid. [H^+] = 0.1\, mol dm^-3 pH = -[H^+] = -(0.1) = 1 The pH value of solution A is 1. Step 4: Identify two solutions that will react to form salt and water. This is an acid-base neutralization reaction. We need one acid and one base. Acids: Solution A (HCl) or Solution B (CH_3COOH). Bases: Solution D (NH_3) or Solution E (NaOH). Two solutions that can react are Solution A (HCl) and Solution E (NaOH). Step 5: Determine the colour of solution C with universal indicator. Solution C is 0.1 mol dm^-3 NaCl, which is a neutral salt. A neutral solution (pH 7) typically turns green with universal indicator. Send me the next one 📸