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Name the circuit symbols.

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Answer

3 Ω\text{3 } \Omega

1

Step-by-step solution

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Part (c)

  1. Name the circuit symbols.

    • II: Resistor
    • III: Switch
    • IV: Voltmeter

  2. Draw the circuit diagram.

    The circuit diagram should show a cell (I), a switch (III), a resistor (II), an ammeter (V) in series with the resistor, and a voltmeter (IV) in parallel across the resistor.

    \begin{circuitikz} \draw (0,0) to[battery] (0,2) to[switch] (2,2) to[ammeter] (4,2) to[R, l_=$II$] (6,2) node[right]{} (6,2) -- (6,0) (6,0) -- (0,0) (6,2) to[voltmeter, v_=$IV$] (6,0) ; \end{circuitikz}

  3. Determine the value of II (Resistance).

    Given:
    Ammeter (V) reading = Current (II) = 5 A
    Voltmeter (IV) reading = Voltage (VV) = 15 V
    Using Ohm's Law, V=IRV = IR.

    R=VIR = \frac{V}{I}

    Substitute the given values:

    R=15 V5 AR = \frac{15\, \text{V}}{5\, \text{A}} R=3 ΩR = 3\, \Omega

    The value of II (resistance) is 3 Ω\boxed{\text{3 } \Omega}.

    Part (d)

  4. Identify solutions based on pH values.

    • (i)(a) pH value equal to 7: Solution C (NaCl is a neutral salt).
    • (i)(b) pH value equal to 14: None of the solutions would have exactly pH 14. However, Solution E (NaOH) is the strongest base listed, with a pH of 13 for 0.1 mol dm−3^{-3}. Assuming the question implies the strongest base, the answer would be Solution E.

  5. Classify solutions.

    • (ii)(a) Strong acid: Solution A (HCl).
    • (ii)(b) Neutral: Solution C (NaCl).
    • (ii)(c) Weak base: Solution D (NH3_3).

  6. Suggest the pH value of solution A.

    Solution A is 0.1 mol dm−3^{-3} HCl, which is a strong acid.

    [H+]=0.1 mol dm−3[H^+] = 0.1\, \text{mol dm}^{-3} pH=−log⁡[H+]=−log⁡(0.1)=1\text{pH} = -\log[H^+] = -\log(0.1) = 1

    The pH value of solution A is 1\boxed{1}.

  7. Identify two solutions that will react to form salt and water.

    This is an acid-base neutralization reaction. We need one acid and one base.

    • Acids: Solution A (HCl) or Solution B (CH3_3COOH).
    • Bases: Solution D (NH3_3) or Solution E (NaOH). Two solutions that can react are Solution A (HCl) and Solution E (NaOH).

  8. Determine the colour of solution C with universal indicator.

    Solution C is 0.1 mol dm−3^{-3} NaCl, which is a neutral salt. A neutral solution (pH 7) typically turns green with universal indicator.

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