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Identify the deposit amount and the fee structure for a cash deposit at a branch counter on 17/12.

Mathematics

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Answer

R19,70\text{R}19,70

Step-by-step solution

3 steps
  1. Identify the deposit amount and the fee structure for a cash deposit at a branch counter on 17/12.

    From Table 1, on 17/12, a cash deposit of R600,00 was made at the branch counter.
    From Table 2, the fee for "Cash deposit: Branch counter" is R8,00 + R1,95 per R100.

  2. Calculate the variable portion of the fee based on the deposit amount.

    The variable fee is R1,95 for every R100 deposited.
    For a R600 deposit, there are R600R100=6\frac{\text{R}600}{\text{R}100} = 6 units of R100.
    Variable fee portion =6×R1,95=R11,70= 6 \times \text{R}1,95 = \text{R}11,70.

  3. Add the fixed fee to the variable fee to find the total deposit fee.

    Total deposit fee =Fixed fee+Variable fee portion= \text{Fixed fee} + \text{Variable fee portion}
    Total deposit fee =R8,00+R11,70=R19,70= \text{R}8,00 + \text{R}11,70 = \text{R}19,70.

    The deposit fee of R19,70 on 17/12 was calculated as:

    Deposit Fee=R8,00+(R600,00R100,00×R1,95)\text{Deposit Fee} = \text{R}8,00 + \left( \frac{\text{R}600,00}{\text{R}100,00} \times \text{R}1,95 \right) Deposit Fee=R8,00+(6×R1,95)\text{Deposit Fee} = \text{R}8,00 + \left( 6 \times \text{R}1,95 \right) Deposit Fee=R8,00+R11,70\text{Deposit Fee} = \text{R}8,00 + \text{R}11,70 Deposit Fee=R19,70\text{Deposit Fee} = \boxed{\text{R}19,70}
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