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Identify the first term and common ratio.

Mathematics

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Answer

B

Step-by-step solution

8 steps
  1. Identify the first term and common ratio.

    The sequence is a geometric progression: 36,12,4,…36, 12, 4, \dots
    The first term is a=36a = 36.
    The common ratio is r=1236=13r = \frac{12}{36} = \frac{1}{3}.

  2. Calculate the sum to infinity.

    The sum to infinity of a geometric progression is given by the formula S∞=a1−rS_{\infty} = \frac{a}{1-r}, provided that ∣r∣<1|r| < 1.
    In this case, ∣r∣=∣13∣<1|r| = \left|\frac{1}{3}\right| < 1, so the sum to infinity exists.

    S∞=361−13S_{\infty} = \frac{36}{1 - \frac{1}{3}} S∞=3633−13S_{\infty} = \frac{36}{\frac{3}{3} - \frac{1}{3}} S∞=3623S_{\infty} = \frac{36}{\frac{2}{3}} S∞=36×32S_{\infty} = 36 \times \frac{3}{2} S∞=18×3S_{\infty} = 18 \times 3 S∞=54S_{\infty} = 54

    The correct option is B.
    The sum to infinity is 54\boxed{\text{54}}.

    27.

  3. Calculate the printing rate.

    The computer prints 2100 words in 5 minutes.
    Rate = Number of wordsTime\frac{\text{Number of words}}{\text{Time}}

    Rate=2100 words5 minutes=420 words/minute\text{Rate} = \frac{2100 \text{ words}}{5 \text{ minutes}} = 420 \text{ words/minute}
  4. Calculate the number of words printed in 6126\frac{1}{2} minutes.

    Time = 6126\frac{1}{2} minutes = 6.5 minutes.
    Number of words = Rate ×\times Time

    Number of words=420 words/minute×6.5 minutes\text{Number of words} = 420 \text{ words/minute} \times 6.5 \text{ minutes} Number of words=420×132\text{Number of words} = 420 \times \frac{13}{2} Number of words=210×13\text{Number of words} = 210 \times 13 Number of words=2730\text{Number of words} = 2730

    The correct option is B.
    The number of words printed is 2730\boxed{\text{2730}}.

    28.
    The number given is 50.999.
    The question asks to express it correct to 3 decimal places.
    If 50.999 is interpreted as the repeating decimal 50.999…50.999\dots, then it is equivalent to 51.
    To express 51 correct to 3 decimal places, we write it as 51.000.
    Among the given options, 51.0 (Option A) is equivalent to 51.000.
    The correct option is A.
    50.999, expressed correct to 3 decimal places, is 51.0\boxed{\text{51.0}}.

    29.
    The number is 4.035.
    We need to find the value of the digit 3.
    The digit 3 is in the hundredths place.
    Its value is 3×1100=0.033 \times \frac{1}{100} = 0.03.
    The correct option is A.
    The value of the digit 3 in 4.035 is 0.03\boxed{\text{0.03}}.

    30.
    The symbol ≤\le means "less than or equal to".
    The correct option is D.
    The symbol ≤\le means Less than or equal to\boxed{\text{Less than or equal to}}.

    31.

  5. Locate point T on the graph.

    By observing the coordinates on the graph, point T is located at x=−2x = -2 and y=−2y = -2.
    The coordinates of point T are (−2,−2)(-2, -2).
    The correct option is B.
    The point T on the graph is (-2, -2)\boxed{\text{(-2, -2)}}.

    32.

  6. Apply the order of operations (PEMDAS/BODMAS).

    Multiplication should be performed before subtraction.

    16−2×316 - 2 \times 3 16−616 - 6 1010

    The correct option is B.
    Evaluating 16−2×316 - 2 \times 3 gives 10\boxed{\text{10}}.

    33.

  7. Simplify the equation of the line.

    The equation of the line is 2y=4x2y = 4x.
    Divide both sides by 2:

    y=2xy = 2x
  8. Check which option satisfies the equation y=2xy = 2x.

    • A (4, 2): 2=2(4)⇒2=82 = 2(4) \Rightarrow 2 = 8 (False)
    • B (1, 2): 2=2(1)⇒2=22 = 2(1) \Rightarrow 2 = 2 (True)
    • C (2, 1): 1=2(2)⇒1=41 = 2(2) \Rightarrow 1 = 4 (False)
    • D (1, 1): 1=2(1)⇒1=21 = 2(1) \Rightarrow 1 = 2 (False) The point (1
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