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Identify the given probability and the event for which the probability is required.

Mathematics

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5 steps

10 (a)

  1. Identify the given probability and the event for which the probability is required.

    The probability of Kasukulu waking up late is P(late)=0.3P(\text{late}) = 0.3.
    The probability of waking up early is the complement of waking up late.

  2. Use the complementary probability formula.

    The sum of the probability of an event and its complement is 1.

    P(early)=1−P(late)P(\text{early}) = 1 - P(\text{late}) P(early)=1−0.3P(\text{early}) = 1 - 0.3 P(early)=0.7P(\text{early}) = 0.7

    The probability that she will wake up early is 0.7\boxed{\textbf{0.7}}.

    10 (b)

  3. State the formula for the area of a sector and identify the given values.

    The area of a sector AA with radius rr and angle θ\theta (in degrees) is given by:

    A=θ360∘πr2A = \frac{\theta}{360^\circ} \pi r^2

    Given:
    A=24.2 cm2A = 24.2 \text{ cm}^2
    r=6 cmr = 6 \text{ cm}
    π=227\pi = \frac{22}{7}

  4. Substitute the given values into the formula.

    24.2=θ360∘×227×(6 cm)224.2 = \frac{\theta}{360^\circ} \times \frac{22}{7} \times (6 \text{ cm})^2 24.2=θ360∘×227×3624.2 = \frac{\theta}{360^\circ} \times \frac{22}{7} \times 36
  5. Simplify the equation and solve for θ\theta.

    24.2=θ×22×36360×724.2 = \theta \times \frac{22 \times 36}{360 \times 7} 24.2=θ×792252024.2 = \theta \times \frac{792}{2520}

    Divide both the numerator and denominator of the fraction by their greatest common divisor, which is 72:

    24.2=θ×113524.2 = \theta \times \frac{11}{35}

    Now, isolate θ\theta:

    θ=24.2×3511\theta = 24.2 \times \frac{35}{11} θ=24210×3511\theta = \frac{242}{10} \times \frac{35}{11} θ=22×1110×3511\theta = \frac{22 \times 11}{10} \times \frac{35}{11} θ=2210×35\theta = \frac{22}{10} \times 35 θ=2.2×35\theta = 2.2 \times 35 θ=77\theta = 77

    The value of θ\theta is \boxed{\textbf{77^\circ}}.

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