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Identify the given quadratic polynomial and its zeroes.

Mathematics

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Q.1.i.

  1. Identify the given quadratic polynomial and its zeroes.

    The quadratic polynomial is x2−3x+kx^2 - 3x + k.
    The zeroes are α=2\alpha = 2 and β=−5\beta = -5.

  2. Use the relationship between the product of zeroes and the coefficients of a quadratic polynomial.

    For a quadratic polynomial ax2+bx+cax^2 + bx + c, the product of the zeroes is given by ca\frac{c}{a}.
    In x2−3x+kx^2 - 3x + k, we have a=1a=1, b=−3b=-3, and c=kc=k.
    The product of the given zeroes is 2×(−5)=−102 \times (-5) = -10.
    Equating this to ca\frac{c}{a}:

    k1=−10\frac{k}{1} = -10 k=−10k = -10

    The correct alternative is (A).
    The final answer is (A) -10\boxed{\text{(A) -10}}.

    Q.1.ii.

  3. Recall the standard trigonometric value for sin⁡30∘\sin 30^\circ.

    The value of sin⁡30∘\sin 30^\circ is a fundamental trigonometric ratio.

    sin⁡30∘=12\sin 30^\circ = \frac{1}{2}

    The correct alternative is (B).
    The final answer is (B) 12\boxed{\text{(B) } \frac{1}{2}}.

    Q.1.iii.

  4. Identify the given points.

    The two points are (x1,y1)=(−2,3)(x_1, y_1) = (-2, 3) and (x2,y2)=(4,−1)(x_2, y_2) = (4, -1).

  5. Use the distance formula.

    The distance DD between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula:

    D=(x2−x1)2+(y2−y1)2D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
  6. Substitute the coordinates and calculate the distance.

    D=(4−(−2))2+(−1−3)2D = \sqrt{(4 - (-2))^2 + (-1 - 3)^2} D=(4+2)2+(−4)2D = \sqrt{(4 + 2)^2 + (-4)^2} D=(6)2+(−4)2D = \sqrt{(6)^2 + (-4)^2} D=36+16D = \sqrt{36 + 16} D=52D = \sqrt{52}

    The correct alternative is (B).
    The final answer is (B) 52\boxed{\text{(B) } \sqrt{52}}.

    Q.1.iv.

  7. Identify the first five natural numbers.

    Natural numbers are positive integers starting from 1.
    The first five natural numbers are $1, 2, 3, 4, 5$.

  8. Calculate the sum of these numbers.

    Sum =1+2+3+4+5=15= 1 + 2 + 3 + 4 + 5 = 15.

  9. Calculate the mean.

    The mean is the sum of the numbers divided by the count of the numbers.
    Count of numbers =5= 5.

    Mean=SumCount=155=3\text{Mean} = \frac{\text{Sum}}{\text{Count}} = \frac{15}{5} = 3

    The correct alternative is (C).
    The final answer is (C) 3\boxed{\text{(C) 3}}.

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