Identify whether this shapes are congruent or similar

Both triangles have all three angles marked as $60^\circ$. This means both are equilateral triangles.

The tick marks on the sides of both triangles indicate that all sides within each triangle are equal, and that the corresponding sides between the two triangles are also equal in length.

Since all corresponding angles are equal ($60^\circ$) and all corresponding side lengths are equal, the two triangles are identical in size and shape.
The shapes are congruent.

The first triangle (ABC) has angles $30^\circ$, $90^\circ$, and $60^\circ$ ($180^\circ - 90^\circ - 30^\circ = 60^\circ$).
The second triangle (PQR) also has angles $30^\circ$, $90^\circ$, and $60^\circ$ ($180^\circ - 90^\circ - 30^\circ = 60^\circ$).
All corresponding angles are equal.

For triangle ABC: $BC = 1$ cm, $AC = 2$ cm, and $AB = \sqrt{3}$ cm (from $AB^2 + 1^2 = 2^2$).
For triangle PQR: $QR = 1$ cm, $PR = 2$ cm, and $PQ = \sqrt{3}$ cm (from $PQ^2 + 1^2 = 2^2$).
All corresponding side lengths are equal ($AB=PQ=\sqrt{3}$ cm, $BC=QR=1$ cm, $AC=PR=2$ cm).

Since all corresponding angles are equal and all corresponding side lengths are equal, the two triangles are identical in size and shape.
The shapes are congruent.

Both shapes are quadrilaterals with two right angles. They are right trapezoids.

The first trapezoid has side lengths 5 cm, 4 cm, and 3 cm, with the 4 cm side being perpendicular to the 5 cm and 3 cm sides.
The second trapezoid also has side lengths 5 cm, 4 cm, and 3 cm, with the 4 cm side being perpendicular to the 5 cm and 3 cm sides.
All corresponding side lengths are equal.

The two quadrilaterals have identical side lengths and angles, they are just oriented differently.
The shapes are congruent.