यदि सुबह 9 बजे किसी व्यक्ति की छाया उसकी ओर ही बन रही है, तो वह किस दिशा में मुंह करके खड़ा है?

March 22, 2026Mathematics

ScanSolve AI Answer

March 22, 2026

Answer

$30 cm^{2}$

Step 1: Verify if $\triangle ABC$ is right-angled at $B$ using Pythagoras theorem.
Formula: $AB^2 + BC^2 \stackrel{?}{=} AC^2$
$AB^2 + BC^2 = 5^2 + 12^2 = 25 + 144 = 169~cm^2$
$AC^2 = 13^2 = 169~cm^2$
Since $AB^2 + BC^2 = AC^2$ , $\triangle ABC$ is right-angled at $B$ .

Step 2: Area of right-angled triangle = $\frac{1}{2} \times$ (product of legs $AB$ and $BC$ ).
$Area = \frac{1}{2} \times AB \times BC = \frac{1}{2} \times 5~cm \times 12~cm$
$= \frac{1}{2} \times 60~cm^2$
$= 30~cm^2$

30 \mathrm{cm^{2}}

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Quick Answer

Verify if ABC is right-angled at B using Pythagoras theorem. Formula: AB^2 + BC^2 ?= AC^2 AB^2 + BC^2 = 5^2 + 12^2 = 25 + 144 = 169~cm^2 AC^2 = 13^2 = 169~cm^2 Since AB^2 + BC^2 = AC^2, ABC is right-angled at B.

Asked on March 22, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on March 22, 2026

Step 1: Verify if ABC is right-angled at B using Pythagoras theorem. Formula: AB^2 + BC^2 ?= AC^2 AB^2 + BC^2 = 5^2 + 12^2 = 25 + 144 = 169~cm^2 AC^2 = 13^2 = 169~cm^2 Since AB^2 + BC^2 = AC^2, ABC is right-angled at B. Step 2: Area of right-angled triangle = (1)/(2) × (product of legs AB and BC). Area = (1)/(2) × AB × BC = (1)/(2) × 5~cm × 12~cm = (1)/(2) × 60~cm^2 = 30~cm^2 30 cm^2