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यदि सुबह 9 बजे किसी व्यक्ति की छाया उसकी ओर ही बन रही है, तो वह किस दिशा में मुंह करके खड़ा है?

March 22, 2026Mathematics

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Answer

30 \mathrm{cm}^{2}

2 steps

Verify if $\triangle ABC$ is right-angled at $B$ using Pythagoras theorem.
Formula: $AB^2 + BC^2 \stackrel{?}{=} AC^2$
$AB^2 + BC^2 = 5^2 + 12^2 = 25 + 144 = 169~\mathrm{cm}^2$ $AC^2 = 13^2 = 169~\mathrm{cm}^2$
Since $AB^2 + BC^2 = AC^2$ , $\triangle ABC$ is right-angled at $B$ .
Area of right-angled triangle = $\frac{1}{2} \times$ (product of legs $AB$ and $BC$ ).
$\text{Area} = \frac{1}{2} \times AB \times BC = \frac{1}{2} \times 5~\mathrm{cm} \times 12~\mathrm{cm}$ $= \frac{1}{2} \times 60~\mathrm{cm}^2$ $= 30~\mathrm{cm}^2$
30 cm^{2}

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