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Determine if Mrs. Baxter will have enough chairs in her class and give a reason for your answer.

Mathematics

ScanSolve AI Answer

Answer

2.6

2.9 m\text{2.9 m}

Step-by-step solution

6 steps

Part 2.1· 2 steps

  1. Count the number of chairs in the classroom layout.

    • Front table: 3 chairs
    • Table near mirror: 4 chairs
    • Back table: 6 chairs
    • Art table: 4 chairs Total chairs = 3+4+6+4=173 + 4 + 6 + 4 = 17 chairs.
  2. Compare the total chairs to the number of students.

    Mrs. Baxter has 18 students but only 17 chairs.
    No, Mrs. Baxter will not have enough chairs for 18 students because there are only 17 chairs available in the classroom.

Part 2.2· 1 step

  1. Identify all labeled exits/doors on the plan.

    • "DOOR TO WORKROOM"
    • "HALLWAY DOOR" There are 2 exits in this classroom.

Part 2.3

A mirror in a preschool classroom can be used for children to observe themselves, aiding in self-awareness and dramatic play.

Part 2.4

Mrs. Baxter should add at least one more chair to accommodate all 18 students. She could also rearrange the tables to create more open space for the "Area for whole class activity" to improve flow.

Part 2.5

Two possible challenges on this layout plan are:

  • Insufficient seating for all students (only 17 chairs for 18 students).
  • The central "Area for whole class activity" might obstruct movement and create congestion, especially with multiple children moving between different activity zones.

Part 2.6

2.9 m\text{2.9 m}

  1. Identify the given scale and measurement.

    Scale = 1:1001 : 100
    Measurement on plan = 29 mm29 \text{ mm}

  2. Calculate the actual length in millimeters.

    Actual length = Plan measurement ×\times Scale factor
    Actual length = 29 mm×100=2900 mm29 \text{ mm} \times 100 = 2900 \text{ mm}

  3. Convert the actual length from millimeters to meters.

    Since 1 m=1000 mm1 \text{ m} = 1000 \text{ mm}:

    Actual length in meters=2900 mm1000 mm/m=2.9 m\text{Actual length in meters} = \frac{2900 \text{ mm}}{1000 \text{ mm/m}} = 2.9 \text{ m}

    The actual length of the front table is 2.9 m\boxed{\text{2.9 m}}.

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