If rope length eighteen cm is use to form a sector of a cycle of radius c.2 cm on a school sport ground calculate the size of the angle of the sector?

Mathematics

ScanSolve AI Answer

Answer

7 radians\text{7 radians}

Step-by-step solution

3 steps
  1. Identify the given values and the formula for the perimeter of a sector.

    The total rope length represents the perimeter of the sector.
    The perimeter PP of a sector is given by the formula P=2r+LP = 2r + L, where rr is the radius and LL is the arc length.
    Given:
    Perimeter P=18P = 18 cm
    Radius r=2r = 2 cm (interpreting "c.2 cm" as 2 cm)

  2. Calculate the arc length LL.

    Substitute the given values into the perimeter formula:

    18=2(2)+L18 = 2(2) + L 18=4+L18 = 4 + L

    Subtract 4 from both sides to find LL:

    L=18−4L = 18 - 4 L=14 cmL = 14 \text{ cm}
  3. Calculate the angle of the sector in radians.

    The formula for arc length is L=rθL = r\theta, where θ\theta is the angle in radians.
    Substitute the values for LL and rr:

    14=2θ14 = 2\theta

    Divide by 2 to find θ\theta:

    θ=142\theta = \frac{14}{2} θ=7 radians\theta = 7 \text{ radians}

    The size of the angle of the sector is 7 radians\text{7 radians}.

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