Verify if the couples (3; -2) and (0; 1) are solutions to the system (S) = x + 2y = 2 x - y = -1

Substitute $x=3$ and $y=-2$ into the equations of the system:
Equation 1: $x + 2y = 2$

$$3 + 2(-2) = 3 - 4 = -1$$

Since $-1 \neq 2$, the couple $(3; -2)$ is not a solution to the system.

Substitute $x=0$ and $y=1$ into the equations of the system:
Equation 1: $x + 2y = 2$

$$0 + 2(1) = 2$$

This equation holds true.

Equation 2: $x - y = -1$

$$0 - 1 = -1$$

This equation also holds true.

Since both equations are satisfied, the couple $(0; 1)$ is a solution to the system.

The couple $(3; -2)$ is not a solution to the system $(S)$, while the couple $(0; 1)$ is a solution to the system $(S)$.