Determine if the following pairs of triangles are congruent. Explain your reasoning, citing the appropriate congruence rule.

Both triangles are right-angled.
The hypotenuse of the first triangle is $72 \text{ mm}$, and the hypotenuse of the second triangle is $72 \text{ mm}$.
One side of the first triangle is $58 \text{ mm}$, and one side of the second triangle is $58 \text{ mm}$.

The triangles are congruent because they are right-angled, have equal hypotenuses, and one pair of corresponding sides are equal. This satisfies the RHS (Right angle - Hypotenuse - Side) rule.

The triangles are congruent by the RHS rule.

For the first triangle, two angles are $40^\circ$ and $60^\circ$, and the included side is $7 \text{ cm}$ ($70 \text{ mm}$).
For the second triangle, two angles are $40^\circ$ and $60^\circ$, and the included side is $70 \text{ mm}$.

Since two angles and the included side are equal in both triangles, they are congruent by the ASA (Angle - Side - Angle) rule.

The triangles are congruent by the ASA rule.

The sides of the first triangle are $4 \text{ cm}$, $6 \text{ cm}$, and $5 \text{ cm}$.
The sides of the second triangle are $6 \text{ cm}$, $5 \text{ cm}$, and $4 \text{ cm}$.

All three corresponding sides of the triangles are equal. This satisfies the SSS (Side - Side - Side) rule.

The triangles are congruent by the SSS rule.