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If Y = house, tree and V = cat, house, tree, which of the following is true of Y and V?

Mathematics

ScanSolve AI Answer

Answer

B

Step-by-step solution

3 steps
  1. Understand the given sets.

    We are given two sets:
    Y={house, tree}Y = \{\text{house, tree}\}
    V={cat, house, tree}V = \{\text{cat, house, tree}\}

  2. Analyze the relationship between the sets.

    We need to determine which statement is true.

    • For Y=VY = V to be true, both sets must contain exactly the same elements. YY has "house" and "tree", while VV has "cat", "house", and "tree". Since VV contains "cat" which is not in YY, Y≠VY \neq V. So, option A is false.
    • For Y⊂VY \subset V (Y is a proper subset of V) to be true, every element of YY must also be an element of VV, and VV must contain at least one element not in YY. The elements of YY are "house" and "tree". Both "house" and "tree" are present in VV. The set VV contains "cat", which is not in YY. Therefore, YY is a proper subset of VV. So, option B is true.
    • For V⊂YV \subset Y (V is a proper subset of Y) to be true, every element of VV must also be an element of YY, and YY must contain at least one element not in VV. The element "cat" is in VV but not in YY. Therefore, VV is not a subset of YY. So, option C is false.
    • For V∈YV \in Y (V is an element of Y) to be true, the entire set VV must be one of the items listed inside the curly braces of YY. The elements of YY are "house" and "tree", not the set VV. So, option D is false.
  3. Conclude the correct statement.

    Based on the analysis, the statement Y⊂VY \subset V is true.

    The correct option is B.
    B. Y⊂V\boxed{\text{B. } Y \subset V}

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