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In the above diagram, what is the length of side XZ?

Mathematics

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Answer

d

c. 14.4 cm\text{c. } 14.4 \text{ cm}

56.3∘56.3^\circ

Step-by-step solution

3 steps

Here are the solutions for questions 8 and 9:

8. In the above diagram, what is the length of side XZ?

Step 1: Identify the given information and the unknown.
We have a right-angled triangle △XYZ\triangle XYZ with the right angle at YY.
The lengths of the two legs are XY=8 cmXY = 8 \text{ cm} and YZ=12 cmYZ = 12 \text{ cm}.
We need to find the length of the hypotenuse XZXZ.

Step 2: Apply the Pythagorean theorem.
The Pythagorean theorem states a2+b2=c2a^2 + b^2 = c^2, where aa and bb are the lengths of the legs and cc is the length of the hypotenuse.

XZ2=XY2+YZ2XZ^2 = XY^2 + YZ^2

Step 3: Substitute the given values and calculate.

XZ2=(8 cm)2+(12 cm)2XZ^2 = (8 \text{ cm})^2 + (12 \text{ cm})^2 XZ2=64 cm2+144 cm2XZ^2 = 64 \text{ cm}^2 + 144 \text{ cm}^2 XZ2=208 cm2XZ^2 = 208 \text{ cm}^2 XZ=208 cm2XZ = \sqrt{208 \text{ cm}^2} XZ≈14.422 cmXZ \approx 14.422 \text{ cm}

Step 4: Select the closest option.
Comparing this value to the given options:

Part a

4.0 cm4.0 \text{ cm}

Part b

8.9 cm8.9 \text{ cm}

Part c

14.4 cm14.4 \text{ cm}

Part d

c. 14.4 cm\text{c. } 14.4 \text{ cm}

20.0 cm20.0 \text{ cm}

The closest option is c.
c. 14.4 cm\boxed{\text{c. } 14.4 \text{ cm}}

9. In the above diagram, what is the measure of ∠X\angle X?

  1. Identify the sides relative to ∠X\angle X.

    From the perspective of ∠X\angle X:
    The side opposite ∠X\angle X is YZ=12 cmYZ = 12 \text{ cm}.
    The side adjacent to ∠X\angle X is XY=8 cmXY = 8 \text{ cm}.

  2. Choose the appropriate trigonometric ratio.

    Since we have the opposite and adjacent sides, we use the tangent function:

    tan⁡X=oppositeadjacent\tan X = \frac{\text{opposite}}{\text{adjacent}} tan⁡X=YZXY\tan X = \frac{YZ}{XY}
  3. Substitute the values and calculate ∠X\angle X.

    tan⁡X=12 cm8 cm\tan X = \frac{12 \text{ cm}}{8 \text{ cm}} tan⁡X=1.5\tan X = 1.5

    To find ∠X\angle X, we take the inverse tangent (arctan) of 1.5:

    X=arctan⁡(1.5)X = \arctan(1.5) X≈56.3∘X \approx 56.3^\circ

    56.3∘\boxed{56.3^\circ}

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