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In the above figure, PQR is a tangent at Q and RST is a straight line. QTU = 50°, UTW = 33° and TRQ = 25°. Giving reasons in each case, calculate (i) Angle TSQ (ii) Angle TSW (iii) Angle TUQ (iv) Angle PQW

Mathematics

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Here's a step-by-step calculation for each angle:

Given information:

  • PQR is a tangent to the circle at Q.
  • RST is a straight line.
  • ∠QTU=50∘\angle QTU = 50^\circ
  • ∠UTW=33∘\angle UTW = 33^\circ
  • ∠TRQ=25∘\angle TRQ = 25^\circ

a) (i) Angle TSQ

  1. Find ∠QTW\angle QTW.

    ∠QTW\angle QTW is the sum of ∠QTU\angle QTU and ∠UTW\angle UTW.

    ∠QTW=∠QTU+∠UTW=50∘+33∘=83∘\angle QTW = \angle QTU + \angle UTW = 50^\circ + 33^\circ = 83^\circ

    Reason: Angles on a straight line (if U is on TW) or Angle addition.

  2. Find ∠RQS\angle RQS.

    By the Alternate Segment Theorem, the angle between the tangent PQR and the chord QS (∠RQS\angle RQS) is equal to the angle subtended by the chord QS in the alternate segment (∠QTW\angle QTW).

    ∠RQS=∠QTW=83∘\angle RQS = \angle QTW = 83^\circ

    Reason: Alternate Segment Theorem.

  3. Find ∠TSQ\angle TSQ.

    Consider △RQS\triangle RQS. The sum of angles in a triangle is 180∘180^\circ.

    ∠RSQ=180∘−(∠TRQ+∠RQS)\angle RSQ = 180^\circ - (\angle TRQ + \angle RQS) ∠RSQ=180∘−(25∘+83∘)\angle RSQ = 180^\circ - (25^\circ + 83^\circ) ∠RSQ=180∘−108∘=72∘\angle RSQ = 180^\circ - 108^\circ = 72^\circ

    Since S is on the line RST, ∠TSQ=∠RSQ\angle TSQ = \angle RSQ.

    ∠TSQ=72∘\angle TSQ = 72^\circ

    Reason: Sum of angles in a triangle.
    The angle TSQ is 72∘\boxed{72^\circ}.

    a) (ii) Angle TSW

  4. Find ∠QSU\angle QSU.

    Angles subtended by the same arc are equal. ∠QSU\angle QSU and ∠QTU\angle QTU are both subtended by arc QU.

    ∠QSU=∠QTU=50∘\angle QSU = \angle QTU = 50^\circ

    Reason: Angles subtended by the same arc.

  5. Find ∠TSU\angle TSU.

    Since S is on the line RST, ∠TSQ=∠TSU+∠QSU\angle TSQ = \angle TSU + \angle QSU.

    ∠TSU=∠TSQ−∠QSU=72∘−50∘=22∘\angle TSU = \angle TSQ - \angle QSU = 72^\circ - 50^\circ = 22^\circ

    Reason: Angle subtraction.

  6. Find ∠TQU\angle TQU.

    Angles subtended by the same arc are equal. ∠TQU\angle TQU and ∠TSU\angle TSU are both subtended by arc TU.

    ∠TQU=∠TSU=22∘\angle TQU = \angle TSU = 22^\circ

    Reason: Angles subtended by the same arc.

  7. Find ∠UQW\angle UQW.

    Angles subtended by the same arc are equal. ∠UQW\angle UQW and ∠UTW\angle UTW are both subtended by arc UW.

    ∠UQW=∠UTW=33∘\angle UQW = \angle UTW = 33^\circ

    Reason: Angles subtended by the same arc.

  8. Find ∠TQW\angle TQW.

    ∠TQW\angle TQW is the sum of ∠TQU\angle TQU and ∠UQW\angle UQW.

    ∠TQW=∠TQU+∠UQW=22∘+33∘=55∘\angle TQW = \angle TQU + \angle UQW = 22^\circ + 33^\circ = 55^\circ

    Reason: Angle addition.

  9. Find ∠TSW\angle TSW.

    Angles subtended by the same arc are equal. ∠TSW\angle TSW and ∠TQW\angle TQW are both subtended by arc TW.

    ∠TSW=∠TQW=55∘\angle TSW = \angle TQW = 55^\circ

    Reason: Angles subtended by the same arc.
    The angle TSW is 55∘\boxed{55^\circ}.

    a) (iii) Angle TUQ

  10. Find ∠QWT\angle QWT.

    By the Alternate Segment Theorem, the angle between the tangent PQR and the chord QT (∠PQT\angle PQT) is equal to the angle subtended by the chord QT in the alternate segment (∠QWT\angle QWT).
    First, find ∠PQT\angle PQT.
    ∠PQT=∠QST\angle PQT = \angle QST. We found ∠QST=∠TSQ=72∘\angle QST = \angle TSQ = 72^\circ in part (i).
    So, ∠PQT=72∘\angle PQT = 72^\circ.
    Therefore, ∠QWT=72∘\angle QWT = 72^\circ.
    Reason: Alternate Segment Theorem.

  11. Find ∠TUQ\angle TUQ.

    Angles subtended by the same arc are equal. ∠TUQ\angle TUQ and ∠QWT\angle QWT are both subtended by arc TQ.

    ∠TUQ=∠QWT=72∘\angle TUQ = \angle QWT = 72^\circ

    Reason: Angles subtended by the same arc.
    The angle TUQ is 72∘\boxed{72^\circ}.

    a) (iv) Angle PQW

  12. Find ∠PQW\angle PQW.

    By the Alternate Segment Theorem, the angle between the tangent PQR and the chord QW (∠PQW\angle PQW) is equal to the angle subtended by the chord QW in the alternate segment (∠QTW\angle QTW).
    We found ∠QTW=83∘\angle QTW = 83^\circ in part (i).

    ∠PQW=∠QTW=83∘\angle PQW = \angle QTW = 83^\circ

    Reason: Alternate Segment Theorem.
    The angle PQW is 83∘\boxed{83^\circ}.

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