We read your photo as:

In the diagram below DE//BC. DE = 2cm, BC = 3cm and AC = 2cm. Determine the value of x.

Mathematics

ScanSolve AI Answer

Step-by-step solution

12 steps

Here are the solutions for , question 1:

1a)

  1. Calculate the third angle for each triangle.

    For the first triangle (ABC):

    ∠A=180∘−55∘−68∘=57∘\angle A = 180^\circ - 55^\circ - 68^\circ = 57^\circ

    The angles are 57∘,55∘,68∘57^\circ, 55^\circ, 68^\circ.
    For the second triangle (PQR):

    ∠R=180∘−55∘−68∘=57∘\angle R = 180^\circ - 55^\circ - 68^\circ = 57^\circ

    The angles are 55∘,68∘,57∘55^\circ, 68^\circ, 57^\circ.

  2. Compare the angles.

    Both triangles have angles 55∘,68∘,57∘55^\circ, 68^\circ, 57^\circ. Since all corresponding angles are equal, the triangles are similar by the Angle-Angle-Angle (AAA) similarity criterion.

  3. State the similar triangles in the correct order.

    Matching angles: ∠A=∠R=57∘\angle A = \angle R = 57^\circ, ∠B=∠P=55∘\angle B = \angle P = 55^\circ, ∠C=∠Q=68∘\angle C = \angle Q = 68^\circ.

    △ABC∼△RPQ\boxed{\triangle ABC \sim \triangle RPQ}

    1b)

  4. Compare the angles.

    The first triangle (ABC) has angles marked with one arc (∠A\angle A) and two arcs (∠B\angle B).
    The second triangle (PQR) has angles marked with one arc (∠P\angle P) and two arcs (∠Q\angle Q).
    This indicates that ∠A=∠P\angle A = \angle P and ∠B=∠Q\angle B = \angle Q.

  5. Determine similarity.

    Since two angles of one triangle are equal to two angles of another triangle, their third angles must also be equal (∠C=∠R\angle C = \angle R). Therefore, the triangles are similar by the Angle-Angle (AA) similarity criterion.

  6. State the similar triangles in the correct order.

    Matching angles: ∠A=∠P\angle A = \angle P, ∠B=∠Q\angle B = \angle Q, ∠C=∠R\angle C = \angle R.

    △ABC∼△PQR\boxed{\triangle ABC \sim \triangle PQR}

    1c)

  7. Calculate the third angle for each triangle.

    For the first triangle (ABC):

    ∠A=180∘−70∘−70∘=40∘\angle A = 180^\circ - 70^\circ - 70^\circ = 40^\circ

    The angles are 40∘,70∘,70∘40^\circ, 70^\circ, 70^\circ.
    For the second triangle (PQR):

    ∠Q=180∘−70∘−70∘=40∘\angle Q = 180^\circ - 70^\circ - 70^\circ = 40^\circ

    The angles are 70∘,40∘,70∘70^\circ, 40^\circ, 70^\circ.

  8. Compare the angles.

    Both triangles have angles 40∘,70∘,70∘40^\circ, 70^\circ, 70^\circ. Since all corresponding angles are equal, the triangles are similar by the Angle-Angle-Angle (AAA) similarity criterion.

  9. State the similar triangles in the correct order.

    Matching angles: ∠A=∠Q=40∘\angle A = \angle Q = 40^\circ, ∠B=∠P=70∘\angle B = \angle P = 70^\circ, ∠C=∠R=70∘\angle C = \angle R = 70^\circ.

    △ABC∼△QPR\boxed{\triangle ABC \sim \triangle QPR}

    1d)

  10. Calculate the third angle for each triangle.

    For the first triangle (ABC):

    ∠C=180∘−69∘−37∘=74∘\angle C = 180^\circ - 69^\circ - 37^\circ = 74^\circ

    The angles are 69∘,37∘,74∘69^\circ, 37^\circ, 74^\circ.
    For the second triangle (PQR):

    ∠Q=180∘−54∘−57∘=69∘\angle Q = 180^\circ - 54^\circ - 57^\circ = 69^\circ

    The angles are 54∘,57∘,69∘54^\circ, 57^\circ, 69^\circ.

  11. Compare the angles.

    The angles of △ABC\triangle ABC are 69∘,37∘,74∘69^\circ, 37^\circ, 74^\circ.
    The angles of △PQR\triangle PQR are 54∘,57∘,69∘54^\circ, 57^\circ, 69^\circ.
    The sets of angles are not identical. Only one angle (69∘69^\circ) is common, but not all three.

  12. Determine similarity.

    Since the corresponding angles are not all equal, the triangles are not similar.

    The triangles are not similar.\boxed{\text{The triangles are not similar.}}
Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp