This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Here are the solutions to the questions:
1.1 Calculate the distance of AB.
Step 1: Use the distance formula with points A and B. Step 2: Simplify the expression. Step 3: Calculate the numerical value. The distance of AB is .
1.2 Determine the midpoint of AC.
Step 1: Use the midpoint formula with points A and C. Step 2: Simplify the coordinates. The midpoint of AC is \boxed{*(-3, 1.5)*}}.
1.3 Determine the gradient of BC.
Step 1: Use the gradient formula with points B and C. Step 2: Simplify the expression. The gradient of BC is \boxed{*\frac{8}{9}*}}.
1.4 Find the equation of the line BC.
Step 1: Use the point-slope form with the gradient and point C. Step 2: Simplify the equation to the form . The equation of the line BC is \boxed{*y = \frac{8}{9}x - 4*}}.
1.5 Determine the inclination angle, , of the line BC.
Step 1: Use the relationship , where is the gradient of BC. Step 2: Calculate the angle . The inclination angle is \boxed{*approximately 41.63^\circ*}}.
1.6 Determine the value of .
Step 1: For ABCD to be a trapezium, at least one pair of opposite sides must be parallel. From the diagram, AD appears parallel to BC. If AD is parallel to BC, their gradients must be equal: . We know from question 1.3. Step 2: Calculate the gradient of AD using points A and D. Step 3: Set and solve for . The value of is \boxed{* -10.5*}}.
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1.1 Calculate the distance of AB. Step 1: Use the distance formula d = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2) with points A(-6, 7) and B(9, 4).
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.