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In the equation 18 x 3 - 2 / 4 + 7 = 59, by interchanging which two numbers can the equation be made correct?

Mathematics

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Answer

2 এবং 4\text{2 এবং 4}

To make the given equation correct, we need to interchange two numbers.
The original equation is:

18×3−2÷4+7=5918 \times 3 - 2 \div 4 + 7 = 59

First, let's evaluate the Left Hand Side (LHS) of the original equation using the order of operations (multiplication and division before addition and subtraction):

18×3−2÷4+718 \times 3 - 2 \div 4 + 7 =54−0.5+7= 54 - 0.5 + 7 =53.5+7= 53.5 + 7 =60.5= 60.5

Since 60.5≠5960.5 \neq 59, the original equation is incorrect. We need to find which interchange makes it correct.

Let's test each option:

  • Option 1: Interchange 7 and 3 The equation becomes:

    18×7−2÷4+3=5918 \times 7 - 2 \div 4 + 3 = 59

    Evaluate LHS:

    18×7−2÷4+318 \times 7 - 2 \div 4 + 3 =126−0.5+3= 126 - 0.5 + 3 =125.5+3= 125.5 + 3 =128.5= 128.5

    Since 128.5≠59128.5 \neq 59, this option is incorrect.

  • Option 2: Interchange 18 and 4 The equation becomes:

    4×3−2÷18+7=594 \times 3 - 2 \div 18 + 7 = 59

    Evaluate LHS:

    4×3−2÷18+74 \times 3 - 2 \div 18 + 7 =12−19+7= 12 - \frac{1}{9} + 7 =12−0.111...+7= 12 - 0.111... + 7 =11.888...+7= 11.888... + 7 =18.888...= 18.888...

    Since 18.888...≠5918.888... \neq 59, this option is incorrect.

  • Option 3: Interchange 3 and 2 The equation becomes:

    18×2−3÷4+7=5918 \times 2 - 3 \div 4 + 7 = 59

    Evaluate LHS:

    18×2−3÷4+718 \times 2 - 3 \div 4 + 7 =36−0.75+7= 36 - 0.75 + 7 =35.25+7= 35.25 + 7 =42.25= 42.25

    Since 42.25≠5942.25 \neq 59, this option is incorrect.

  • Option 4: Interchange 2 and 4 The equation becomes:

    18×3−4÷2+7=5918 \times 3 - 4 \div 2 + 7 = 59

    Evaluate LHS:

    18×3−4÷2+718 \times 3 - 4 \div 2 + 7 =54−2+7= 54 - 2 + 7 =52+7= 52 + 7 =59= 59

    Since 59=5959 = 59, this option makes the equation correct.

The final answer is 2 এবং 4\text{2 এবং 4}

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