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Find the inverse function and determine if the relation is a function. Also, find the equation for g(x) and its inverse.

Mathematics

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Step-by-step solution

5 steps

2.1.1
To find the inverse function f−1(x)f^{-1}(x) from a set of ordered pairs, we swap the xx and yy coordinates for each pair.
Given f(x)={(−2;3),(0;−1),(1;2),(2;0)}f(x) = \{(-2; 3), (0; -1), (1; 2), (2; 0)\}.

f−1(x)={(3;−2),(−1;0),(2;1),(0;2)}f^{-1}(x) = \{(3; -2), (-1; 0), (2; 1), (0; 2)\}

The inverse function is {(3;−2),(−1;0),(2;1),(0;2)}\boxed{\{(3; -2), (-1; 0), (2; 1), (0; 2)\}}.

2.1.2
A relation is a function if each input (x-value) corresponds to exactly one output (y-value).
In the given set f(x)={(−2;3),(0;−1),(1;2),(2;0)}f(x) = \{(-2; 3), (0; -1), (1; 2), (2; 0)\}, all the x-values (−2,0,1,2-2, 0, 1, 2) are unique. Therefore, each x-value has only one corresponding y-value.
f(x)f(x) is a function.

2.2.1
The equation for g(x)g(x) is given as y=axy = a^x.
We are given that the point A(4; 8) lies on the graph of g(x)g(x). We can substitute these coordinates into the equation to find the value of aa.

  1. Substitute the coordinates of A(4; 8) into y=axy = a^x.

    8=a48 = a^4
  2. Solve for aa.

    a=84a = \sqrt[4]{8}

    We can also write 8 as 232^3, so a=(23)1/4=23/4a = (2^3)^{1/4} = 2^{3/4}.

  3. Write the equation for g(x)g(x).

    y=(23/4)xy = (2^{3/4})^x

    This can also be written as y=8x/4y = 8^{x/4}.
    The equation for g(x)g(x) is y=8x/4\boxed{y = 8^{x/4}}.

    2.2.2
    To determine the equation of g−1(x)g^{-1}(x), we first swap xx and yy in the equation for g(x)g(x). The question asks for the answer in the form x=...x = ....

  4. Start with the equation for g(x)g(x).

    y=8x/4y = 8^{x/4}
  5. Swap xx and yy to find the inverse relation.

    x=8y/4x = 8^{y/4}

    The equation of g−1(x)g^{-1}(x) in the form x=...x = ... is x=8y/4\boxed{x = 8^{y/4}}.

    2.2.3
    The function g(x)=8x/4g(x) = 8^{x/4} is an exponential function. Exponential functions of the form y=bxy = b^x have a horizontal asymptote at y=0y=0.
    The inverse function g−1(x)g^{-1}(x) is a logarithmic function. The asymptote of an inverse function is found by swapping the variables of the original function's asymptote.
    Since g(x)g(x) has a horizontal asymptote at y=0y=0, its inverse g−1(x)g^{-1}(x) will have a vertical asymptote at x=0x=0.
    The equation for the asymptote of g−1(x)g^{-1}(x) is x=0\boxed{x = 0}.

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