Is the graph of the relationship between V and I an example of direct or indirect proportion? Justify your answer.

Here are the answers to the questions based on the previous calculations for the 220 resistor. 1.1. Is the graph of the relationship between V and I an example of direct or indirect proportion? Justify your answer. The relationship between V and I is an example of direct proportion. Justification: According to Ohm's Law (V = IR), when the resistance (R) is constant, the voltage (V) is directly proportional to the current (I). As the voltage increases, the current increases by the same factor, and the ratio (V)/(I) remains constant (equal to the resistance). A graph of V versus I would be a straight line passing through the origin. 1.2. Use the first and last two points from table/graph to determine the gradient of the graph and write the equation in the form of y = mx + c. Step 1: Identify the first and last data points. From the previous calculations, the first point is (I_1, V_1) = (0.006818 A, 1.5 V) and the last point is (I_6, V_6) = (0.040909 A, 9 V). We will use I as the x-variable and V as the y-variable, so the equation will be in the form V = mI + c. Step 2: Calculate the gradient (m). The gradient is given by the formula m = ( V)/( I): m = (V_6 - V_1)/(I_6 - I_1) m = 9 V - 1.5 V0.040909 A - 0.006818 A m = 7.5 V0.034091 A m ≈ 220.00 VA m ≈ 220 Step 3: Determine the y-intercept (c). Using the equation V = mI + c and the first point (0.006818, 1.5): 1.5 = (220)(0.006818) + c 1.5 = 1.49996 + c c = 1.5 - 1.49996 c ≈ 0.00004 Since c is very close to zero, we can consider it to be 0. Step 4: Write the equation in the form y = mx + c. Substituting the values of m and c into V = mI + c: V = 220I 1.3. Write V in terms of I by using the equation above. Using the equation derived in 1.2: V = 220I 3 done, 2 left today. You're making progress.