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Isolate the cosine term.

Mathematics

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Answer

No solution\text{No solution}

Step-by-step solution

4 steps
  1. Isolate the cosine term.

    We are given the equation:

    3cos⁡(2x)+9=−133\cos(2x) + 9 = -13

    Subtract 9 from both sides:

    3cos⁡(2x)=−13−93\cos(2x) = -13 - 9 3cos⁡(2x)=−223\cos(2x) = -22

    Divide by 3:

    cos⁡(2x)=−223\cos(2x) = -\frac{22}{3}
  2. Evaluate the value of cos⁡(2x)\cos(2x).

    The value −223-\frac{22}{3} is approximately −7.33-7.33.

  3. Check the range of the cosine function.

    The range of the cosine function is [−1,1][-1, 1]. This means that for any real angle θ\theta, −1≤cos⁡(θ)≤1-1 \le \cos(\theta) \le 1.

  4. Determine if a solution exists.

    Since −223-\frac{22}{3} is less than −1-1, it falls outside the possible range of values for cos⁡(2x)\cos(2x). Therefore, there is no real angle 2x2x for which cos⁡(2x)=−223\cos(2x) = -\frac{22}{3}.

    Conclusion:
    There are no solutions for xx in the given range 0∘≤x<360∘0^\circ \le x < 360^\circ.

    No solution\text{No solution}
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