How to get the critical values

Mathematics

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Answer

x=2 and x=−1x = 2 \text{ and } x = -1

Step-by-step solution

4 steps

To find the critical values where the two functions f(x)=x2f(x) = x^2 and g(x)=x+2g(x) = x+2 intersect, you need to set them equal to each other and solve for xx.

  1. Set f(x)f(x) equal to g(x)g(x).

    f(x)=g(x)f(x) = g(x) x2=x+2x^2 = x+2
  2. Rearrange the equation into a standard quadratic form (ax2+bx+c=0ax^2 + bx + c = 0).

    Subtract xx and 2 from both sides:

    x2−x−2=0x^2 - x - 2 = 0
  3. Solve the quadratic equation for xx.

    You can solve this by factoring, using the quadratic formula, or completing the square. Factoring is often the quickest method if possible.
    We need two numbers that multiply to −2-2 and add to −1-1. These numbers are −2-2 and 1.

    (x−2)(x+1)=0(x-2)(x+1) = 0
  4. Set each factor equal to zero and solve for xx.

    x−2=0  ⟹  x=2x-2 = 0 \implies x = 2 x+1=0  ⟹  x=−1x+1 = 0 \implies x = -1

    The critical values (x-coordinates of the intersection points) are x=2 and x=−1\boxed{x = 2 \text{ and } x = -1}.

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