Solve it for me

The given equations are:

$$3x - 2y = 18 \quad (1)$$ $$x + 2y = 6 \quad (2)$$

Add equation (1) and equation (2):

$$(3x - 2y) + (x + 2y) = 18 + 6$$ $$3x + x - 2y + 2y = 24$$ $$4x = 24$$

Divide both sides by 4:

$$\frac{4x}{4} = \frac{24}{4}$$ $$x = 6$$

Using equation (2):

$$x + 2y = 6$$

Substitute $x = 6$:

$$6 + 2y = 6$$

Subtract 6 from both sides:

$$2y = 6 - 6$$ $$2y = 0$$

Divide by 2:

$$y = \frac{0}{2}$$ $$y = 0$$

The solution to the system of equations is $x=6$ and $y=0$.

The solution is $x=6, y=0$.