It takes y years for N 87,300.00 to amount to N 99,522.00 at 7% per annum simple interest. Find the value of y.

Here are the solutions for questions 3, 4, and 5. Question 3: It takes y years for N 87,300.00 to amount to N 99,522.00 at 7% per annum simple interest. Find the value of y. Step 1: Calculate the simple interest (I). The simple interest is the difference between the amount and the principal. I = Amount - Principal I = N 99,522.00 - N 87,300.00 = N 12,222.00 Step 2: Use the simple interest formula to find y. The formula for simple interest is I = P × R × T, where P is the principal, R is the annual interest rate (as a decimal), and T is the time in years. Given P = N 87,300, R = 7\% = 0.07, and I = N 12,222. 12,222 = 87,300 × 0.07 × y Step 3: Solve for y. 12,222 = 6111 × y y = (12,222)/(6111) y = 2 The value of y is 2 years. The correct option is C. C. 2 Question 4: Given that 3a - 2b = 12 and a + 5b = -13, find the value of (4a - b). Step 1: Solve the system of linear equations for a and b. We have two equations: 1) 3a - 2b = 12 2) a + 5b = -13 From equation (2), express a in terms of b: a = -13 - 5b Substitute this expression for a into equation (1): 3(-13 - 5b) - 2b = 12 -39 - 15b - 2b = 12 -39 - 17b = 12 -17b = 12 + 39 -17b = 51 b = (51)/(-17) b = -3 Step 2: Substitute the value of b back into the expression for a. a = -13 - 5(-3) a = -13 + 15 a = 2 Step 3: Calculate the value of (4a - b). 4a - b = 4(2) - (-3) 4a - b = 8 + 3 4a - b = 11 The correct option is D. D. 11 Question 5: A line in the x-y plane passes through the point (-9, 10). If the gradient of the line is (1)/(3), find the equation of the line. Step 1: Use the point-slope form of a linear equation. The point-slope form is y - y_1 = m(x - x_1), where (x_1, y_1) is a point on the line and m is the gradient (slope). Given point (x_1, y_1) = (-9, 10) and gradient m = (1)/(3). Step 2: Substitute the given values into the formula. y - 10 = (1)/(3)(x - (-9)) y - 10 = (1)/(3)(x + 9) Step 3: Simplify the equation to the slope-intercept form (y = mx + c). y - 10 = (1)/(3)x + (1)/(3) × 9 y - 10 = (1)/(3)x + 3 Add 10 to both sides of the equation: y = (1)/(3)x + 3 + 10 y = (1)/(3)x + 13 This can also be written as y = (x)/(3) + 13. The correct option is C. C. y = (x)/(3) + 13 That's 3 down. 2 left today — send the next one.