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Jembi bought 2 kg of brand A and 3 kg of brand B for sh. 900. Amoit bought 1 kg of brand A and 2 kg of brand B for sh. 550. Find the cost of 1 kg of brand A and 1 kg of brand B.

Mathematics

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Step-by-step solution

4 steps
  1. Define variables and set up the system of equations.

    Let aa be the cost of one kilogram of brand A rice.
    Let bb be the cost of one kilogram of brand B rice.

    From the problem statement, we can form two linear equations:
    Jembi bought 2 kg of brand A and 3 kg of brand B for sh. 900:

    2a+3b=900(1)2a + 3b = 900 \quad (1)

    Amoit bought 1 kg of brand A and 2 kg of brand B for sh. 550:

    a+2b=550(2)a + 2b = 550 \quad (2)
  2. Solve the system of equations using the elimination method.

    Multiply equation (2) by 2 to make the coefficients of aa equal:

    2×(a+2b)=2×5502 \times (a + 2b) = 2 \times 550 2a+4b=1100(3)2a + 4b = 1100 \quad (3)
  3. Subtract equation (1) from equation (3) to eliminate aa and solve for bb.

    (2a+4b)−(2a+3b)=1100−900(2a + 4b) - (2a + 3b) = 1100 - 900 b=200b = 200
  4. Substitute the value of bb back into equation (2) to solve for aa.

    a+2(200)=550a + 2(200) = 550 a+400=550a + 400 = 550 a=550−400a = 550 - 400 a=150a = 150

    The cost of one kilogram of brand A rice is sh. 150.
    The cost of one kilogram of brand B rice is sh. 200.

    The cost of one kilogram of brand A rice is sh. 150\boxed{\text{sh. 150}}.
    The cost of one kilogram of brand B rice is sh. 200\boxed{\text{sh. 200}}.

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