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A vendor spends up to K18 000 to buy soya pieces of type A and B. He buys at most 30 packets total, and at least 5 of each. A packet of A costs K400, B costs K900. Profit on A is K20, on B is K25. Write inequalities for this scenario.

Mathematics

ScanSolve AI Answer

Answer

4x+9y≤1804x + 9y \le 180

Step-by-step solution

2 steps

a) Let xx be the number of packets of soya pieces of type A and yy be the number of packets of soya pieces of type B.

  1. Write the inequality for the total cost.

    A packet of type A costs K400, and a packet of type B costs K900. The vendor can spend up to K18 000.

    400x+900y≤18000400x + 900y \le 18000

    Divide by 100 to simplify:

    4x+9y≤180\boxed{4x + 9y \le 180}
  2. Write the inequality for the total number of packets.

    The vendor does not want to buy more than 30

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