Two grades of rice A and B costing 160 per bag and x per kg respectively are mixed in the ratio 3:1bso that by selling the mixture at 195 a profit of 30% is realized find the cost of B

We assume "160 per bag" for rice A implies 160 per kg, as the selling price is per kg and the ratio is by weight. The cost of rice B is given as 'x' per kg.

• Cost of rice A ($C_A$) = 160 per kg
• Cost of rice B ($C_B$) = x per kg

• The rice is mixed in a ratio of 3:1 (A:B). Let's consider 3 kg of A and 1 kg of B for a total of 4 kg of mixture.
• Cost of 3 kg of A = $3 \text{ kg} \times 160 \text{/kg} = 480$
• Cost of 1 kg of B = $1 \text{ kg} \times x \text{/kg} = x$
• Total CP of 4 kg mixture = $480 + x$

• The mixture is sold at 195 per kg.
• Total SP of 4 kg mixture = $4 \text{ kg} \times 195 \text{/kg} = 780$

• Profit = 30%
• The formula relating SP, CP, and profit is: SP = CP $\times$ (1 + Profit Percentage / 100)
• $780 = (480 + x) \times (1 + 30/100)$
• $780 = (480 + x) \times (1 + 0.30)$
• $780 = (480 + x) \times 1.30$

• $480 + x = 780 / 1.30$
• $480 + x = 600$
• $x = 600 - 480$
• $x = 120$

Therefore, the cost of B is 120 per kg.