We read your photo as:

Jinsi ya kuhesabu na kuonyesha uhusiano kati ya fomula za index na logarithmic kwa kutumia mfumo wa samaki?

Mathematics

ScanSolve AI Answer

Answers

2 parts
a

2414 samaki\text{2414 samaki}

c

10.2 miaka\text{10.2 miaka}

Step-by-step solution

14 steps

Haya, hapa kuna suluhisho la swali lako:

Item 1

Part a· 4 steps

Kutumia mfumo wa index P(t)=1200×(1.15)tP(t) = 1200 \times (1.15)^t kukokotoa idadi ya samaki mwaka 2025.

  1. Kokotoa idadi ya miaka tt.

    Mwaka wa kuanzia ni 2020 na mwaka unaotakiwa ni 2025.

    t=2025−2020=5t = 2025 - 2020 = 5
  2. Badilisha t=5t=5 kwenye mfumo.

    P(5)=1200×(1.15)5P(5) = 1200 \times (1.15)^5
  3. Kokotoa thamani.

    P(5)=1200×2.0113571875P(5) = 1200 \times 2.0113571875 P(5)=2413.628625P(5) = 2413.628625
  4. Zungusha jibu kwa namba kamili ya samaki.

    Idadi ya samaki inayotarajiwa mwaka 2025 ni 2414 samaki\boxed{\text{2414 samaki}}.

Part b· 4 steps

Kuonyesha kuwa mfumo wa logarithmic ni sawa na mfumo wa index.

Mfumo wa index ni P=1200×(1.15)tP = 1200 \times (1.15)^t.
Mfumo wa logarithmic ni log⁡10P=log⁡101200+tlog⁡101.15\log_{10} P = \log_{10} 1200 + t \log_{10} 1.15.

  1. Anza na mfumo wa index.

    P=1200×(1.15)tP = 1200 \times (1.15)^t
  2. Chukua logarithm ya base 10 pande zote mbili.

    log⁡10P=log⁡10(1200×(1.15)t)\log_{10} P = \log_{10} (1200 \times (1.15)^t)
  3. Tumia sheria ya logarithm log⁡(AB)=log⁡A+log⁡B\log(AB) = \log A + \log B.

    log⁡10P=log⁡101200+log⁡10(1.15)t\log_{10} P = \log_{10} 1200 + \log_{10} (1.15)^t
  4. Tumia sheria ya logarithm log⁡(AB)=Blog⁡A\log(A^B) = B \log A.

    log⁡10P=log⁡101200+tlog⁡101.15\log_{10} P = \log_{10} 1200 + t \log_{10} 1.15

    Hii inaonyesha kuwa mfumo wa logarithmic ni sawa na mfumo wa index.

Part c

10.2 miaka\text{10.2 miaka}

Kuamua idadi ya miaka (t) itakayochukua kwa idadi ya samaki kufikia 5,000.

  1. Weka P(t)=5000P(t) = 5000 kwenye mfumo wa index.

    5000=1200×(1.15)t5000 = 1200 \times (1.15)^t
  2. Gawanya pande zote mbili kwa 1200.

    50001200=(1.15)t\frac{5000}{1200} = (1.15)^t 256=(1.15)t\frac{25}{6} = (1.15)^t 4.1666...=(1.15)t4.1666... = (1.15)^t
  3. Chukua logarithm ya base 10 pande zote mbili.

    log⁡10(256)=log⁡10((1.15)t)\log_{10} \left(\frac{25}{6}\right) = \log_{10} ((1.15)^t)
  4. Tumia sheria ya logarithm log⁡(AB)=Blog⁡A\log(A^B) = B \log A.

    log⁡10(256)=tlog⁡10(1.15)\log_{10} \left(\frac{25}{6}\right) = t \log_{10} (1.15)
  5. Tatua kwa tt.

    t=log⁡10(256)log⁡10(1.15)t = \frac{\log_{10} \left(\frac{25}{6}\right)}{\log_{10} (1.15)}
  6. Kokotoa thamani za logarithm na tt.

    t=0.6197890.0606978t = \frac{0.619789}{0.0606978} t≈10.21t \approx 10.21

    Idadi ya miaka itakayochukua ni takriban 10.2 miaka\boxed{\text{10.2 miaka}}.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp