Josephat travelled for 1.5 hours at 116 km/hr, then rested for 30 minutes, and finally travelled 150 km at 60 km/hr. Find the distance he covered before resting and his average speed for the whole jou

Speed ($S_1$) = $116 \text{ km/hr}$
Time ($T_1$) = $1\frac{1}{2}$ hours = $1.5 \text{ hours}$

The distance he covered before resting is $\boxed{\text{174 km}}$.

Distance before resting ($D_1$) = $174 \text{ km}$ (from part a)
Distance after resting ($D_2$) = $150 \text{ km}$
Total Distance ($D_{total}$) = $D_1 + D_2$

Time for the first leg ($T_1$) = $1.5 \text{ hours}$
Resting time ($T_{rest}$) = $30 \text{ minutes} = \frac{30}{60} \text{ hours} = 0.5 \text{ hours}$
Speed for the second leg ($S_2$) = $60 \text{ km/hr}$
Distance for the second leg ($D_2$) = $150 \text{ km}$
Time for the second leg ($T_2$) = $\frac{D_2}{S_2}$

Total Time ($T_{total}$) = $T_1 + T_{rest} + T_2$

Average Speed = $\frac{\text{Total Distance}}{\text{Total Time}}$

Josephat's average speed for the whole journey is $\boxed{\text{72 km/hr}}$.