Calculate the LCM of 2 and 6, and simplify the following fractions: 8/5, n/(n-2) (with n<2), and (n+2)/(n2-1) (with n<1).

The LCM of 2 and 6 is $\boxed{\text{6}}$.

The prime factors of 8 are $2 \times 2 \times 2$.
The prime factors of 5 are 5.
There are no common prime factors other than 1.
The fraction is already in its simplest form.
The simplified expression is $\boxed{\frac{8}{5}}$.

2. Simplify $\frac{n}{n-2}$ with the condition $(n < 2)$.

The numerator is $n$. The denominator is $(n-2)$.
These two terms do not share any common factors.
The expression is already in its simplest form. The condition $n < 2$ ensures that the denominator $n-2 \neq 0$.
The simplified expression is $\boxed{\frac{n}{n-2}}$.

3. Simplify $\frac{n+2}{n^2-1}$ with the condition $(n < 1)$.

The denominator $n^2-1$ is a difference of squares, which factors as $(n-1)(n+1)$.

The numerator is $(n+2)$. The factors in the denominator are $(n-1)$ and $(n+1)$.
There are no common factors.
The expression is already in its simplest form. The condition $n < 1$ ensures that the denominator $(n-1)(n+1) \neq 0$.
The simplified expression is $\boxed{\frac{n+2}{(n-1)(n+1)}}$.