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Multiply all terms by the least common multiple (LCM) of the denominators (4 and 5), which is 20, to clear the fractions.

Mathematics

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1. a) Solve for x in the linear inequality: 14(x+2)<15x+3\frac{1}{4}(x+2) < \frac{1}{5}x + 3

Step 1: Multiply all terms by the least common multiple (LCM) of the denominators (4 and 5), which is 20, to clear the fractions.

20⋅14(x+2)<20⋅15x+20⋅320 \cdot \frac{1}{4}(x+2) < 20 \cdot \frac{1}{5}x + 20 \cdot 3 5(x+2)<4x+605(x+2) < 4x + 60

Step 2: Distribute the 5 on the left side.

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