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Find the length of the diagonal of a rectangular garden measuring 6 m by 8 cm. Assume dimensions are 6m and 8m.

Mathematics

ScanSolve AI Answer

Answer

10 m\text{10 m}

Step-by-step solution

4 steps

The problem asks to find the length of the diagonal of a rectangular garden that measures 6 m by 8 cm. There appears to be a unit inconsistency (meters and centimeters). Assuming the diagram is correct and the dimensions are 6 m and 8 m, we will proceed with that assumption. If the 8 cm is correct, please clarify.

  1. Identify the dimensions of the rectangle.

    The length of the rectangle is 8 m8 \text{ m} and the width is 6 m6 \text{ m}. The diagonal of a rectangle forms the hypotenuse of a right-angled triangle with the length and width as its legs.

  2. Apply the Pythagorean theorem.

    Let dd be the length of the diagonal, ll be the length, and ww be the width. The Pythagorean theorem states:

    d2=l2+w2d^2 = l^2 + w^2
  3. Substitute the given values into the formula.

    d2=(8 m)2+(6 m)2d^2 = (8 \text{ m})^2 + (6 \text{ m})^2 d2=64 m2+36 m2d^2 = 64 \text{ m}^2 + 36 \text{ m}^2 d2=100 m2d^2 = 100 \text{ m}^2
  4. Solve for dd.

    d=100 m2d = \sqrt{100 \text{ m}^2} d=10 md = 10 \text{ m}

    The length of the diagonal is 10 m\text{10 m}.

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