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Find the length of the following pair of points.

Mathematics

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Answer

252\sqrt{5}

17\sqrt{17}

22\frac{\sqrt{2}}{2}

Step-by-step solution

8 steps

Here is the solution for question 5 from the image.

5. Find the length of the following pair of point

The distance formula between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:

D=(x2−x1)2+(y2−y1)2D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

(1) (−3,4)(-3,4) and (−5,0)(-5,0)

  1. Identify the coordinates.

    Let (x1,y1)=(−3,4)(x_1, y_1) = (-3, 4) and (x2,y2)=(−5,0)(x_2, y_2) = (-5, 0).

  2. Substitute the coordinates into the distance formula.

    D=(−5−(−3))2+(0−4)2D = \sqrt{(-5 - (-3))^2 + (0 - 4)^2} D=(−5+3)2+(−4)2D = \sqrt{(-5 + 3)^2 + (-4)^2} D=(−2)2+16D = \sqrt{(-2)^2 + 16} D=4+16D = \sqrt{4 + 16} D=20D = \sqrt{20}
  3. Simplify the radical.

    D=4×5D = \sqrt{4 \times 5} D=25D = 2\sqrt{5}

    The final answer for 5(1) is 25\boxed{2\sqrt{5}}.

    (2) (2,0)(2,0) and (3,4)(3,4)

  4. Identify the coordinates.

    Let (x1,y1)=(2,0)(x_1, y_1) = (2, 0) and (x2,y2)=(3,4)(x_2, y_2) = (3, 4).

  5. Substitute the coordinates into the distance formula.

    D=(3−2)2+(4−0)2D = \sqrt{(3 - 2)^2 + (4 - 0)^2} D=(1)2+(4)2D = \sqrt{(1)^2 + (4)^2} D=1+16D = \sqrt{1 + 16} D=17D = \sqrt{17}

    The final answer for 5(2) is 17\boxed{\sqrt{17}}.

    (3) (12,1)(\frac{1}{2}, 1) and (1,12)(1, \frac{1}{2})

  6. Identify the coordinates.

    Let (x1,y1)=(12,1)(x_1, y_1) = (\frac{1}{2}, 1) and (x2,y2)=(1,12)(x_2, y_2) = (1, \frac{1}{2}).

  7. Substitute the coordinates into the distance formula.

    D=(1−12)2+(12−1)2D = \sqrt{(1 - \frac{1}{2})^2 + (\frac{1}{2} - 1)^2} D=(22−12)2+(12−22)2D = \sqrt{(\frac{2}{2} - \frac{1}{2})^2 + (\frac{1}{2} - \frac{2}{2})^2} D=(12)2+(−12)2D = \sqrt{(\frac{1}{2})^2 + (-\frac{1}{2})^2} D=14+14D = \sqrt{\frac{1}{4} + \frac{1}{4}} D=24D = \sqrt{\frac{2}{4}} D=12D = \sqrt{\frac{1}{2}}
  8. Rationalize the denominator.

    D=12×22D = \frac{1}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} D=22D = \frac{\sqrt{2}}{2}

    The final answer for 5(3) is 22\boxed{\frac{\sqrt{2}}{2}}.

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