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Calculate the distance between the points (3, 7) and (5, 8), and find their midpoint.

Mathematics

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  1. Find the distance between the points $(3, 7)$ and $(5, 8)$.

    The distance formula between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:

    D=(x2−x1)2+(y2−y1)2D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

    Given points are (x1,y1)=(3,7)(x_1, y_1) = (3, 7) and (x2,y2)=(5,8)(x_2, y_2) = (5, 8).

    Substitute the coordinates into the distance formula:

    D=(5−3)2+(8−7)2D = \sqrt{(5 - 3)^2 + (8 - 7)^2} D=(2)2+(1)2D = \sqrt{(2)^2 + (1)^2} D=4+1D = \sqrt{4 + 1} D=5D = \sqrt{5}

    The distance between the points is 5\sqrt{5}.

  2. Find the mid-point of the points $(3, 7)$ and $(5, 8)$.

    The midpoint formula for two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:

    M=(x1+x22,y1+y22)M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)

    Given points are (x1,y1)=(3,7)(x_1, y_1) = (3, 7) and (x2,y2)=(5,8)(x_2, y_2) = (5, 8).

    Substitute the coordinates into the midpoint formula:

    M=(3+52,7+82)M = \left(\frac{3 + 5}{2}, \frac{7 + 8}{2}\right) M=(82,152)M = \left(\frac{8}{2}, \frac{15}{2}\right) M=(4,152)M = \left(4, \frac{15}{2}\right)

    The midpoint of the points is (4,152)\left(4, \frac{15}{2}\right).

    a) The distance between the points is 5\boxed{\sqrt{5}}.

    b) The mid-point of the points is (4,152)\boxed{\left(4, \frac{15}{2}\right)}.

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