Let R be the real area of the land. The title shows 13.5 hectares, which is 10% less than the real area.

The title shows 13.5 hectares, which is 10% less than the real area.
This can be expressed as:

The real area of the land is $\boxed{\text{15 hectares}}$.

From the problem statement, we have two conditions:

1. The PIN is three times the sum of its digits: $$10x + y = 3(x + y) \quad (1)$$
2. The second digit is five more than the first digit: $$y = x + 5 \quad (2)$$

The PIN is $10(2) + 7 = 20 + 7 = 27$.
The 2-digit PIN for the suitcase is $\boxed{\text{27}}$.

Let $f = 0.666...$
Multiply by 10: $10f = 6.666...$
Subtract the first equation from the second:

The simplified fraction of the whole land used for agriculture is $\boxed{\frac{2}{3}}$.

From part a), the real area of the land is 15 hectares.
Area for agriculture = (fraction for agriculture) $\times$ (real area of land)

The real area of the land for agriculture is $\boxed{\text{10 hectares}}$.

Total real area of land = 15 hectares (from part a).
Area used for agriculture = 10 hectares (from part c).

The problem states $\frac{1}{5}$ of the remaining land is sold.

The selling price is shs 50 millions per hectare.

The amount of money to get from the sell of land is $\boxed{\text{shs } 50,000,000}$.

2 zimekamilika. Zimebaki 3 leo — tuma inayofuata.