Step 1: Determine the fraction of land remaining after the son's share. The son was given $\frac{1}{3}$ of the land. The remaining land is the total land (represented by 1) minus the son's share. $$ \text{Remaining land after son} = 1 - \frac{1}{3} = \frac{3}{3} - \frac{1}{3} = \frac{2}{3} $$ Step 2: Determine the fraction of land given to the daughter. The daughter was given $\frac{1}{4}$ of the remaining land. $$ \text{Daughter's share} = \frac{1}{4} \times \left(\frac{2}{3}\right) = \frac{2}{12} = \frac{1}{6} $$ Step 3: Determine the fraction of land remaining for the parents. The land remaining for the parents is the total land minus the son's share and the daughter's share. $$ \text{Parents' share} = 1 - \text{Son's share} - \text{Daughter's share} $$ $$ \text{Parents' share} = 1 - \frac{1}{3} - \frac{1}{6} $$ To subtract these fractions, find a common denominator, which is 6. $$ \text{Parents' share} = \frac{6}{6} - \frac{2}{6} - \frac{1}{6} $$ $$ \text{Parents' share} = \frac{6 - 2 - 1}{6} = \frac{3}{6} = \frac{1}{2} $$ Alternatively, after the son took $\frac{1}{3}$, $\frac{2}{3}$ of the land remained. The daughter took $\frac{1}{4}$ of this remaining land. This means $1 - \frac{1}{4} = \frac{3}{4}$ of that remaining land was left for the parents. $$ \text{Parents' share} = \frac{3}{4} \times \left(\frac{2}{3}\right) = \frac{6}{12} = \frac{1}{2} $$ The fraction of the land that remained for the parents is $\boxed{\frac{1}{2}}$. That's 2 down. 3 left today — send the next one.