Calculate the fraction of the farm given to the wife and the first child.

The wife received $\frac{2}{5}$ of the acres.
The first child received $\frac{1}{3}$ of the acres.
The combined fraction received by the wife and the first child is:

The remaining fraction of the farm is $1 - \frac{11}{15}$:

This $\frac{4}{15}$ of the total farm was shared among the three children in the ratio $3:5:2$.

The sum of the ratio parts is $3 + 5 + 2 = 10$ parts.
The child who had the least share corresponds to the smallest part in the ratio, which is 2 parts.
We are given that the child with the least share received 8 acres.
So, 2 parts = 8 acres.
Therefore, 1 part = $\frac{8 \text{ acres}}{2} = 4 \text{ acres}$.

The total acres shared among the three children is 10 parts:
Total acres for three children = $10 \times 4 \text{ acres} = 40 \text{ acres}$.

We know that the 40 acres represents $\frac{4}{15}$ of the total farm $T$.

To find $T$, multiply both sides by $\frac{15}{4}$:

i) The total acres of the man left (meaning the total acres of the farm) is $\boxed{\text{150 acres}}$.

The wife received $\frac{2}{5}$ of the total acres $T$.

ii) The number of acres the wife received is $\boxed{\text{60 acres}}$.