Let T be the total acres of the cocoa farm.
Step 1: Calculate the fraction of the farm given to the wife and the first child.
The wife received 52 of the acres.
The first child received 31 of the acres.
The combined fraction received by the wife and the first child is:
52+31=5×32×3+3×51×5=156+155=1511
Step 2: Calculate the fraction of the farm remaining for the other three children.
The remaining fraction of the farm is 1−1511:
1−1511=1515−1511=154
This 154 of the total farm was shared among the three children in the ratio 3:5:2.
Step 3: Determine the total parts in the ratio and the value of one part.
The sum of the ratio parts is 3+5+2=10 parts.
The child who had the least share corresponds to the smallest part in the ratio, which is 2 parts.
We are given that the child with the least share received 8 acres.
So, 2 parts = 8 acres.
Therefore, 1 part = 28acres=4 acres.
Step 4: Calculate the total acres shared among the three children.
The total acres shared among the three children is 10 parts:
Total acres for three children = 10×4acres=40 acres.
Step 5: Calculate the total acres of the farm (T).
We know that the 40 acres represents 154 of the total farm T.
154T=40acres
To find T, multiply both sides by 415:
T=40×415
T=10×15
T=150acres
i) The total acres of the man left (meaning the total acres of the farm) is 150acres.
Step 6: Calculate the number of acres the wife received.
The wife received 52 of the total acres T.
Wife′sacres=52×150acres
Wife′sacres=2×5150acres
Wife′sacres=2×30acres
Wife′sacres=60acres
ii) The number of acres the wife received is 60acres.