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A farmer decides to distribute his land among his three children. The first child gets 2/5 of the land, and the second child gets 1/3 of the land. The third child gets the rest. b) Calculate how many

Mathematics

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Answer

c

6:5:4\text{6:5:4}

Step-by-step solution

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Haya, nimekuelewa. Hapa kuna suluhisho la maswali yako:

Part b· 4 steps

Calculate how many hectares each child receives.

  1. Pata sehemu ya ardhi aliyopata mtoto wa kwanza.

    Mtoto wa kwanza alipata 25\frac{2}{5} ya ardhi.

  2. Pata sehemu ya ardhi aliyopata mtoto wa pili.

    Mtoto wa pili alipata 13\frac{1}{3} ya ardhi.

  3. Pata sehemu ya ardhi aliyopata mtoto wa tatu.

    Mtoto wa tatu alipata ardhi iliyobaki. Kwanza, jumlisha sehemu za watoto wawili wa kwanza:

    25+13\frac{2}{5} + \frac{1}{3}

    Ili kujumlisha, tafuta kigawo cha kawaida, ambacho ni 15:

    2×35×3+1×53×5=615+515=1115\frac{2 \times 3}{5 \times 3} + \frac{1 \times 5}{3 \times 5} = \frac{6}{15} + \frac{5}{15} = \frac{11}{15}

    Sasa, toa jumla hii kutoka kwenye ardhi yote (ambayo ni 1, au 1515\frac{15}{15}):

    Sehemu ya mtoto wa tatu=1−1115=1515−1115=415\text{Sehemu ya mtoto wa tatu} = 1 - \frac{11}{15} = \frac{15}{15} - \frac{11}{15} = \frac{4}{15}
  4. Hesabu hekta kwa kila mtoto.

    Jumla ya eneo la ardhi katika hekta haijatolewa katika sehemu inayoonekana ya swali. Ili kukokotoa idadi kamili ya hekta anazopata kila mtoto, jumla ya eneo la ardhi inahitajika.
    Ikiwa tutachukua jumla ya ardhi kuwa LL hekta:

    • Mtoto wa kwanza anapata: 25L\frac{2}{5} L hekta.
    • Mtoto wa pili anapata: 13L\frac{1}{3} L hekta.
    • Mtoto wa tatu anapata: 415L\frac{4}{15} L hekta.

Part c

6:5:4\text{6:5:4}

Express the ratio of land distribution among the three children in simplest form.

  1. Andika sehemu za ardhi kwa kila mtoto.

    Mtoto wa kwanza: 25\frac{2}{5}
    Mtoto wa pili: 13\frac{1}{3}
    Mtoto wa tatu: 415\frac{4}{15}

  2. Unda uwiano wa sehemu hizi.

    Uwiano=25:13:415\text{Uwiano} = \frac{2}{5} : \frac{1}{3} : \frac{4}{15}
  3. Rahisisha uwiano kwa kutafuta kigawo cha kawaida na kuzidisha.

    Kigawo kidogo cha kawaida (LCM) cha vigawanyo 5, 3, na 15 ni 15.
    Zidisha kila sehemu ya uwiano kwa 15:

    (25×15):(13×15):(415×15)\left(\frac{2}{5} \times 15\right) : \left(\frac{1}{3} \times 15\right) : \left(\frac{4}{15} \times 15\right) (2×3):(1×5):(4×1)(2 \times 3) : (1 \times 5) : (4 \times 1) 6:5:46 : 5 : 4

    Uwiano huu uko katika hali yake rahisi zaidi kwa sababu 6, 5, na 4 hazina vigawo vya kawaida isipokuwa 1.

    Uwiano wa ugawaji wa ardhi ni: 6:5:4\boxed{\text{6:5:4}}

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