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Let x = (58.72 x 406)/(0.845).

Mathematics

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2 parts
a

w2+3w−180=0w^2 + 3w - 180 = 0

b

12 m12 \text{ m}

15 m15 \text{ m}

Step-by-step solution

12 steps

Step 1: Let x=58.72×4060.845x = \frac{58.72 \times 406}{0.845}.

Step 2: Take the logarithm (base 10) of both sides.

log⁡x=log⁡(58.72×4060.845)\log x = \log \left(\frac{58.72 \times 406}{0.845}\right)

Step 3: Apply logarithm properties log⁡(AB)=log⁡A+log⁡B\log(AB) = \log A + \log B and log⁡(AB)=log⁡A−log⁡B\log(\frac{A}{B}) = \log A - \log B.

log⁡x=log⁡(58.72)+log⁡(406)−log⁡(0.845)\log x = \log(58.72) + \log(406) - \log(0.845)

Step 4: Find the logarithm values.

log⁡(58.72)≈1.76878\log(58.72) \approx 1.76878 log⁡(406)≈2.60852\log(406) \approx 2.60852 log⁡(0.845)≈−0.07319\log(0.845) \approx -0.07319

Step 5: Substitute the values and calculate log⁡x\log x.

log⁡x=1.76878+2.60852−(−0.07319)\log x = 1.76878 + 2.60852 - (-0.07319) log⁡x=1.76878+2.60852+0.07319\log x = 1.76878 + 2.60852 + 0.07319 log⁡x=4.45049\log x = 4.45049

Step 6: Find the antilogarithm of log⁡x\log x.

x=104.45049x = 10^{4.45049} x≈28214.9x \approx 28214.9

Rounding to a reasonable number of significant figures (e.g., 4 or 5).

x≈28215x \approx 28215

The evaluated value is 28215\boxed{28215}.

Part a· 5 steps

Form quadratic equation to represent this situation.

  1. Let the width of the rectangular plot be ww metres.

  2. The length of the plot is 3 metres more than its width, so the length l=w+3l = w + 3 metres.

  3. The area of a rectangle is given by length ×\times width.

    The total area is 180 m2^2.

    Area=l×w\text{Area} = l \times w 180=(w+3)w180 = (w+3)w
  4. Expand the equation.

    180=w2+3w180 = w^2 + 3w
  5. Rearrange the equation into the standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.

    w2+3w−180=0w^2 + 3w - 180 = 0

    The quadratic equation is w2+3w−180=0\boxed{w^2 + 3w - 180 = 0}.

Part b

12 m12 \text{ m}

Solve the equation by factorisation method to find the dimensions of the plot.

  1. The quadratic equation is w2+3w−180=0w^2 + 3w - 180 = 0.

  2. Find two numbers that multiply to -180 and add to 3.

    These numbers are 15 and -12.

  3. Rewrite the middle term using these numbers.

    w2+15w−12w−180=0w^2 + 15w - 12w - 180 = 0
  4. Factor by grouping.

    w(w+15)−12(w+15)=0w(w + 15) - 12(w + 15) = 0 (w−12)(w+15)=0(w - 12)(w + 15) = 0
  5. Set each factor to zero and solve for ww.

    w−12=0⇒w=12w - 12 = 0 \Rightarrow w = 12 w+15=0⇒w=−15w + 15 = 0 \Rightarrow w = -15
  6. Since width cannot be negative, we take the positive value for ww.

    w=12 mw = 12 \text{ m}
  7. Calculate the length using l=w+3l = w + 3.

    l=12+3=15 ml = 12 + 3 = 15 \text{ m}

    The dimensions of the plot are:
    Width = 12 m\boxed{12 \text{ m}}
    Length = 15 m\boxed{15 \text{ m}}

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