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Let x = theta. Substitute x into the expression to form a quadratic equation.

Mathematics

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Answer

(2cos⁡θ+3)(cos⁡θ+5)(2 \cos \theta + 3)(\cos \theta + 5)

Step-by-step solution

5 steps

To resolve the expression 2cos⁡2θ+13cos⁡θ+152 \cos^2 \theta + 13 \cos \theta + 15 into factors.

  1. Let x=cos⁡θx = \cos \theta.

    Substitute xx into the expression to form a quadratic equation.

    2x2+13x+152x^2 + 13x + 15
  2. Factor the quadratic expression by splitting the middle term.

    We need two numbers that multiply to 2×15=302 \times 15 = 30 and add up to 13. These numbers are 3 and 10.

    2x2+3x+10x+152x^2 + 3x + 10x + 15
  3. Group the terms and factor out common factors from each group.

    (2x2+3x)+(10x+15)(2x^2 + 3x) + (10x + 15) x(2x+3)+5(2x+3)x(2x + 3) + 5(2x + 3)
  4. Factor out the common binomial factor (2x+3)(2x + 3).

    (2x+3)(x+5)(2x + 3)(x + 5)
  5. Substitute back cos⁡θ\cos \theta for xx.

    (2cos⁡θ+3)(cos⁡θ+5)(2 \cos \theta + 3)(\cos \theta + 5)
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