Two cars X and Y, start from a common point and travel in opposite directions. X travels at an average speed of 60 km/h and Y at 80 km/h on the same course. Determine, how far apart X and Y will be after 3 hours.

The initial donation in 2010 is P = \7,000$. The annual increase rate is$r = 8% = 0.08$. The number of years from 2010 to 2012 is$n = 2012 - 2010 = 2$ years.

The formula for the amount after $n$ years is $A = P(1 + r)^n$. $A_{2012} = \$7,000 (1 + 0.08)^2$ $A_{2012} = \$7,000 (1.08)^2$ $A_{2012} = \$7,000 \times 1.1664$

$A_{2012} = \$8,164.80$ The donation given in 2012 is \boxed{\text{\8,164.80}}$.

b) Find the total amount of money donated from 2010 to 2013.

Donation in 2010 ($A_{2010}$) = \7,000$Donation in 2011 ($A_{2011}$) =$$7,000 (1.08)^1 = $7,000 \times 1.08 = $7,560$Donation in 2012 ($A_{2012}$) =$$7,000 (1.08)^2 = $7,000 \times 1.1664 = $8,164.80$Donation in 2013 ($A_{2013}$) =$$7,000 (1.08)^3 = $7,000 \times 1.259712 = $8,817.984$

Total amount = $A_{2010} + A_{2011} + A_{2012} + A_{2013}$
Total amount = \7,000 + $7,560 + $8,164.80 + $8,817.984$

Total amount = \31,542.784$

Total amount = \31,542.78$The total amount of money donated from 2010 to 2013 is$\boxed{\text{$31,542.78}}$.

:

a) Determine how far apart X and Y will be after 3 hours.

Speed of car X ($S_X$) = 60 km/h
Speed of car Y ($S_Y$) = 80 km/h
Time ($t$) = 3 hours
The cars travel in opposite directions.

Distance traveled by X ($D_X$) = $S_X \times t = 60 \text{ km/h} \times 3 \text{ h} = 180 \text{ km}$
Distance traveled by Y ($D_Y$) = $S_Y \times t = 80 \text{ km/h} \times 3 \text{ h} = 240 \text{ km}$

Since they travel in opposite directions from a common point, their total distance apart is the sum of the distances each traveled.
Total distance apart = $D_X + D_Y = 180 \text{ km} + 240 \text{ km} = 420 \text{ km}$
Alternatively, using relative speed:
Relative speed = $S_X + S_Y = 60 \text{ km/h} + 80 \text{ km/h} = 140 \text{ km/h}$
Total distance apart = Relative speed $\times$ Time = $140 \text{ km/h} \times 3 \text{ h} = 420 \text{ km}$
Cars X and Y will be $\boxed{\text{420 km}}$ apart after 3 hours.