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Let's find the H.C.F. of the following numbers by factorisation method. e) 36, 48 f) 30, 75, 90 g) 32, 64, 80

Mathematics

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here are the solutions for questions 4 (continued) and 5:

4. Let's find the H.C.F. of the following numbers by factorisation method.

e) 36, 48

  1. Find the prime factorization of each number.

    36=2×2×3×3=22×3236 = 2 \times 2 \times 3 \times 3 = 2^2 \times 3^2 48=2×2×2×2×3=24×3148 = 2 \times 2 \times 2 \times 2 \times 3 = 2^4 \times 3^1
  2. Identify the common prime factors and their lowest powers.

    The common prime factors are 222^2 and 313^1.

  3. Multiply these common prime factors.

    H.C.F.=22×31=4×3=12\text{H.C.F.} = 2^2 \times 3^1 = 4 \times 3 = 12

    H.C.F. of 36 and 48 is 12\boxed{\text{12}}.

    f) 30, 75, 90

  4. Find the prime factorization of each number.

    30=2×3×5=21×31×5130 = 2 \times 3 \times 5 = 2^1 \times 3^1 \times 5^1 75=3×5×5=31×5275 = 3 \times 5 \times 5 = 3^1 \times 5^2 90=2×3×3×5=21×32×5190 = 2 \times 3 \times 3 \times 5 = 2^1 \times 3^2 \times 5^1
  5. Identify the common prime factors and their lowest powers.

    The common prime factors are 313^1 and 515^1.

  6. Multiply these common prime factors.

    H.C.F.=31×51=3×5=15\text{H.C.F.} = 3^1 \times 5^1 = 3 \times 5 = 15

    H.C.F. of 30, 75, and 90 is 15\boxed{\text{15}}.

    g) 32, 64, 80

  7. Find the prime factorization of each number.

    32=2×2×2×2×2=2532 = 2 \times 2 \times 2 \times 2 \times 2 = 2^5 64=2×2×2×2×2×2=2664 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 2^6 80=2×2×2×2×5=24×5180 = 2 \times 2 \times 2 \times 2 \times 5 = 2^4 \times 5^1
  8. Identify the common prime factors and their lowest powers.

    The common prime factor is 242^4.

  9. Calculate the value.

    H.C.F.=24=16\text{H.C.F.} = 2^4 = 16

    H.C.F. of 32, 64, and 80 is 16\boxed{\text{16}}.

    h) 96, 144, 216

  10. Find the prime factorization of each number.

    96=25×3196 = 2^5 \times 3^1 144=24×32144 = 2^4 \times 3^2 216=23×33216 = 2^3 \times 3^3
  11. Identify the common prime factors and their lowest powers.

    The common prime factors are 232^3 and 313^1.

  12. Multiply these common prime factors.

    H.C.F.=23×31=8×3=24\text{H.C.F.} = 2^3 \times 3^1 = 8 \times 3 = 24

    H.C.F. of 96, 144, and 216 is 24\boxed{\text{24}}.

    5. Let's find the H.C.F. of the following numbers by division method.

    a) 18, 24

  13. Divide the larger number (24) by the smaller number (18).

    24=18×1+624 = 18 \times 1 + 6
  14. Divide the previous divisor (18) by the remainder (6).

    18=6×3+018 = 6 \times 3 + 0

    The last non-zero remainder is the H.C.F.
    H.C.F. of 18 and 24 is 6\boxed{\text{6}}.

    b) 28, 32

  15. Divide 32 by 28.

    32=28×1+432 = 28 \times 1 + 4
  16. Divide 28 by 4.

    28=4×7+028 = 4 \times 7 + 0

    H.C.F. of 28 and 32 is 4\boxed{\text{4}}.

    c) 36, 42

  17. Divide 42 by 36.

    42=36×1+642 = 36 \times 1 + 6
  18. Divide 36 by 6.

    36=6×6+036 = 6 \times 6 + 0

    H.C.F. of 36 and 42 is 6\boxed{\text{6}}.

    d) 52, 65

  19. Divide 65 by 52.

    65=52×1+1365 = 52 \times 1 + 13
  20. Divide 52 by 13.

    52=13×4+052 = 13 \times 4 + 0

    H.C.F. of 52 and 65 is 13\boxed{\text{13}}.

    e) 35, 56, 70

  21. Find the H.C.F.

    of the first two numbers, 35 and 56.
    Divide 56 by 35:

    56=35×1+2156 = 35 \times 1 + 21

    Divide 35 by 21:

    35=21×1+1435 = 21 \times 1 + 14

    Divide 21 by 14:

    21=14×1+721 = 14 \times 1 + 7

    Divide 14 by 7:

    14=7×2+014 = 7 \times 2 + 0

    The H.C.F. of 35 and 56 is 7.

  22. Find the H.C.F.

    of the result (7) and the third number (70).
    Divide 70 by 7:

    70=7×10+070 = 7 \times 10 + 0

    H.C.F. of 35, 56, and 70 is 7\boxed{\text{7}}.

    f) 30, 45, 60

  23. Find the H.C.F.

    of the first two numbers, 30 and 45.
    Divide 45 by 30:

    45=30×1+1545 = 30 \times 1 + 15

    Divide 30 by 15:

    30=15×2+030 = 15 \times 2 + 0

    The H.C.F. of 30 and 45 is 15.

  24. Find the H.C.F.

    of the result (15) and the third number (60).
    Divide 60 by 15:

    60=15×4+060 = 15 \times 4 + 0

    H.C.F. of 30, 45, and 60 is 15\boxed{\text{15}}.

    g) 156, 221, 390

  25. Find the H.C.F.

    of the first two numbers, 156 and 221.
    Divide 221 by 156:

    221=156×1+65221 = 156 \times 1 + 65

    Divide 156 by 65:

    156=65×2+26156 = 65 \times 2 + 26

    Divide 65 by 26:

    65=26×2+1365 = 26 \times 2 + 13

    Divide 26 by 13:

    26=13×2+026 = 13 \times 2 + 0

    The H.C.F. of 156 and 221 is 1

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